java - 将所有最后的元素拆分并存储到一个数组中

Question

我想将检索到的字符串值存储到一个数组或列表中，然后对它们进行排序。我已经尝试了很多方法来以上述方式存储它们。但没有任何帮助。有人可以在这方面帮助我吗。

List<WebElement> list = webDriver.findElements(By.xpath(expression));
int listcount = list.size();    
List optionsList = null;
String options[] = new String[listcount];

for (int i=1; i<=listcount; i++) {                     
    options[i-1] = webDriver.findElement(By.xpath("expression")).getText();
    //contains three words eg: Test Engineer Madhu               
    String[] expectedOptions = options[i-1].split(" ");
    //splitting based on the space           
    String lastName =expectedOptions[expectedOptions.length-1]; 
    //taking the lastName.
    List<String> strArray = new ArrayList<String>();
    for (int k = 0; k < i; k++) {
       strArray.add(lastName);        
    }
    optionsList = Arrays.asList(lastName);
}          
System.out.println(optionsList);
//This always results in last option's last name eg: [Madhu]
}      

现在，我希望将所有姓氏存储在一个数组中，以验证它们是否按排序顺序排列。

Answer 1

这里是获取数组中所有姓氏的修改代码

List<WebElement> list = webDriver.findElements(By.xpath(expression));
int listcount = list.size();    
List optionsList = null;
String options[] = new String[listcount];

for (int i=1; i<=listcount; i++) 
{                     
    options[i-1] = webDriver.findElement(By.xpath("expression")).getText();
    //contains three words eg: Test Engineer Madhu               
    String[] expectedOptions = options[i-1].split(" ");
    //splitting based on the space           
    // I hope the next line gives you the correct lastName
    String lastName =expectedOptions[expectedOptions.length-1]; 
    // lets store the last name in the array
    options[i-1] = lastName;        
 }         
 optionsList = Arrays.asList(options);
 // Iterate through the list to see all last names.