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java - 井字游戏 'X' 直到第二个 'O' 被点击后才出现

转载 作者:行者123 更新时间:2023-11-30 10:51:04 24 4
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你好,我一直在用 Java 开发一个井字游戏应用程序并且我已经运行了,但我的问题是当我与 X 对战时,在我点击放置第一个 O 的位置​​后 X 不可见。 X在那里,但在我点击第二个点作为我的第二个 O 之前它是不可见的。我不明白为什么。我将在下面提供代码。

public class TicTacToeApp{
public static void main(String[] args){
TicTacToeView view = new TicTacToeView();
TicTacToeModel model = new TicTacToeModel();
TicTacToeViewController controller = new TicTacToeViewController(view,model);
view.setVisible(true);
}
}

public class TicTacToeModel {

double xpos,ypos,xr,yr;
char[][] position = {{' ',' ',' '},
{' ',' ',' '},
{' ',' ',' '}};

/**
* Turns row, col into the center of the cells of any screen of resolution h by w.
* This is ideal for the view.
*/
public void computePos(int row, int col, int h, int w){
xpos=(col+0.5)*w/3.0;
ypos=(row+0.5)*h/3.0;
xr=w/8.0;
yr=h/8.0;
}

/**
* returns true if the cell at xpos ypos is blank
* Validates that xpos and ypos are within range.
*/
public boolean isEmpty(int xpos, int ypos){
if(position[xpos][ypos]==' ')
{
return true;
}
return false;
}

/*
* Places an O at position xpos and ypos. No additional validation.
*/
public void placeO(int xpos, int ypos) {
position[xpos][ypos]='O';
}

/**
* Really dumb strategy for the computer to play tic-tac-toe.
* Places an X in the next available space from left to right and
* top to bottom.
*/
public int putX(){
for(int i=0; i<3;i++)
for(int j = 0;j<3;j++) {
if(position[i][j]==' ') {
position[i][j]='X';
return 0;
}
}
return -1; //some error occurred. This is odd. No cells were free.
}


public void printBoard(){
for(int i=0;i<3;i++)
System.out.println(position[i][0]+"|"+position[i][1]+"|"+position[i] [2]);
}
}

  import java.awt.*;
import javax.swing.*;
import java.awt.event.*;
import java.awt.geom.*;
import javax.swing.*;
import javax.swing.event.*;
import java.util.ArrayList;

public class TicTacToeView extends JFrame{

private JButton oButton, xButton;
public JPanel board;
public ArrayList<Shape> shapes;

public TicTacToeView(){
shapes = new ArrayList<Shape>();
JPanel topPanel=new JPanel();
topPanel.setLayout(new FlowLayout());
add(topPanel, BorderLayout.NORTH);
add(board=new Board(), BorderLayout.CENTER);
setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
setSize(500, 500);
}


private class Board extends JPanel {
public void paintComponent(Graphics g) {
super.paintComponent(g);
int w=getWidth();
int h=getHeight();
Graphics2D g2d = (Graphics2D) g;

// Draw the grid
g2d.setPaint(Color.WHITE);
g2d.fill(new Rectangle2D.Double(0, 0, w, h));
g2d.setPaint(Color.BLACK);
g2d.setStroke(new BasicStroke(4));
g2d.draw(new Line2D.Double(0, h/3, w, h/3));
g2d.draw(new Line2D.Double(0, h*2/3, w, h*2/3));
g2d.draw(new Line2D.Double(w/3, 0, w/3, h));
g2d.draw(new Line2D.Double(w*2/3, 0, w*2/3, h));
//draw circles and xs by visiting elements in the array List.
for(Shape shape : shapes){
g2d.setPaint(Color.BLUE);
g2d.draw(shape);
}
}
}

/*
* Adds the mouse listener passed to Board.
*/
public void addMouseListener(MouseListener ml){
board.addMouseListener(ml);
}


public static void main(String[] args) {
TicTacToeView ttv = new TicTacToeView();
ttv.setVisible(true);

}
}



import java.awt.event.*;
import java.awt.geom.*;
import java.awt.Graphics2D;
import java.awt.Color;
import javax.swing.JOptionPane;

/*
* This is the controller for the tic-tac-toe.
* Notice that it implements a MouseListener that
* can be attached to a graphical component and therefore
* complies with the interface MouseListener.
*/
public class TicTacToeViewController implements MouseListener{

TicTacToeView view;
TicTacToeModel model;
Color oColor=Color.BLUE, xColor=Color.RED;

    public TicTacToeViewController(TicTacToeView view, TicTacToeModel model) { 
this.view = view;
this.model = model;
// do this
view.addMouseListener(this);
}

/** Ask the model what's the next move.
*/
public void play(int ypos, int xpos) {
if (model.isEmpty(xpos,ypos)) {// changed x and y because it lands in the wrong position.
// TO DO: Put the O in xpos ypos using the model.
model.placeO(xpos,ypos);
// TO DO: Put the X using the model.
drawBoard();
view.repaint();
model.putX();


}
// TO DO: add the conditions inside the () of the if's that determine the winner.
if( didWin('X') )
JOptionPane.showMessageDialog(null,"X Wins","Winner", JOptionPane.INFORMATION_MESSAGE);
else if ( didWin('O') )
JOptionPane.showMessageDialog(null,"O Wins","Winner",JOptionPane.INFORMATION_MESSAGE);
}


/** Control the drawing of O and X.
* This looks at the model to see where there are Xs and Os and draws two diagonal
* lines or a circle (an Ellipse, actually) in the positions given.
*/
public void drawBoard() {
Graphics2D g2d = (Graphics2D)view.board.getGraphics();

for (int i=0; i<3; i++)
for(int j=0; j<3;j++) {
model.computePos(i,j,view.board.getHeight(),view.board.getWidth());
double xpos = model.xpos;
double xr = model.xr;
double ypos = model.ypos;
double yr = model.yr;
// TODO: Complete the expressions within the if statements as follows:
// if the array that represents the board has a O in position i, j... else,
// if it has an X...
if ( model.position[i][j]=='O' ) {
// Adds a circle (which is an Ellipse of sorts) to the list of elements to draw
view.shapes.add(new Ellipse2D.Double(xpos-xr, ypos-yr, xr*2, yr*2));
}
if (model.position[i][j]=='X' ) {
// Adds two lines crossed (the X) to the list of shapes to draw.
view.shapes.add(new Line2D.Double(xpos-xr, ypos-yr, xpos+xr, ypos+yr));
view.shapes.add(new Line2D.Double(xpos-xr, ypos+yr, xpos+xr, ypos-yr));
}
System.out.println("Coords: xpos:"+xpos+", ypos:"+ypos+", xr"+xr+", yr"+yr);
}
}

/** MouseListener event
* Converts the coordinates of the mouse into the corresponding row and column of the cell
*/
public void mouseClicked(MouseEvent e) {
int xpos=e.getX()*3/view.getWidth();
int ypos=e.getY()*3/view.getHeight();
//System.out.println("Play "+xpos+","+ypos);
play(xpos,ypos);
}

/**
* Check wheather player has won. Checks happen against the model.
*/
public boolean didWin(char player) {
// TO DO
int count = 0;
int count2 = 0;

for(int i = 0; i < 3; i++)
{

for(int j = 0; j<3; j++)
{

if(model.position[i][j]== player)
{
count++;
if(count == 3 )
return true;
}
}
count = 0;
}
for(int n = 0; n < 3; n++)
{
for(int n2=0; n2 <3; n2++)
{
if(model.position[n][n2]==player)
{
count2++;
if(count2 == 3)// if doesnt work change back to 2
return true;
}
} count2=0;
}
if(model.position[0][0]==player && model.position[1][1]==player && model.position[2][2]==player)
return true;

if(model.position[0][2]==player && model.position[1][1]==player && model.position[2][0]==player)
return true;






return false;
}




/** Ignore other mouse events*/
public void mousePressed(MouseEvent e) {}
public void mouseReleased(MouseEvent e) {}
public void mouseEntered(MouseEvent e) {}
public void mouseExited(MouseEvent e) {}
}

最佳答案

在 TicTacToe Controller 类中的 play 方法中,您应该在 model.putX() 方法之后调用 drawBoard() 和 view.repaint()

model.putX();
drawBoard();
view.repaint();

完整方法

 public void play(int ypos, int xpos) {
if (model.isEmpty(xpos,ypos)) {// changed x and y because it lands in the wrong position.
// TO DO: Put the O in xpos ypos using the model.
model.placeO(xpos,ypos);
// TO DO: Put the X using the model.
drawBoard();
view.repaint();
model.putX();
drawBoard();
view.repaint();



}
// TO DO: add the conditions inside the () of the if's that determine the winner.
if( didWin('X') )
JOptionPane.showMessageDialog(null,"X Wins","Winner", JOptionPane.INFORMATION_MESSAGE);
else if ( didWin('O') )
JOptionPane.showMessageDialog(null,"O Wins","Winner",JOptionPane.INFORMATION_MESSAGE);
}

关于java - 井字游戏 'X' 直到第二个 'O' 被点击后才出现,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/34831377/

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