javascript - IF 语句不起作用

Question

很抱歉，如果我正在做一些非常愚蠢的事情，但我无法让这个 IF 语句工作...

它的作用是检查 cookie 中的某些值，设置组合框默认值。

通过调试我看到所有的cookie变量都是正确的，但是if语句好像没有读到值？前两个 IF 正常工作，但最后一个 else-if 不工作。

非常感谢任何帮助，谢谢

function checkBody() {
   var cookie1 = readCookie("Text Colour");
   textCol = cookie1 ? cookie1 : "#444";

   var cookie2 = readCookie("Background Colour");
   backCol = cookie2 ? cookie2 : "white";

   var cookie3 = readCookie("Link Colour");
   linkCol = cookie3 ? cookie3 : "#0424B5";

   var cookie4 = readCookie("Heading1 Colour");
   heading1Col = cookie4 ? cookie4 : "#0424B5";

   var cookie5 = readCookie("Headings Colour");
   headingsCol = cookie5 ? cookie5 : "#99975A";

   var element = document.getElementById('colours');
   if(textCol == cookie1 && backCol == cookie2)
      element.value = "#444,white,#0424B5,#0424B5,#99975A";
   else if(textCol == cookie1 && backCol == cookie2)
      element.value = "black,yellow,black,black,black";
   else if(textCol == cookie1 && backCol == cookie2)
      element.value = "black,#87CEFA,black,black,black";

   bodyStyle(textCol,backCol,linkCol,heading1Col,headingsCol);
}

Answer 1

所有的 if 都是一样的。后两者从未达到。

...
else if(textCol == cookie1 && backCol == cookie2)
    element.value = "black,yellow,black,black,black";
else if(textCol == cookie1 && backCol == cookie2)
    element.value = "black,#87CEFA,black,black,black";
...