swift - 带时间类型的日期选择器

Question

时间选择器不允许我设置最大时间，我正在使用以下代码行:

    let formatter = DateFormatter()
    formatter.dateFormat = "hh:mm a"
    let locale = NSLocale(localeIdentifier: "en_US_POSIX")
    formatter.locale = locale as Locale

    timePicker.datePickerMode = .time


    let min = formatter.date(from: "08:00 AM") //createing mintime
    let max = formatter.date(from: "11:00 PM") //creating max time

    print(max)

    timePicker.minimumDate = min  //setting min time to picker
    timePicker.maximumDate = max  //setting max time to picker

    timePicker.minuteInterval = 30

Answer 1

使用以下代码设置最短和最长时间，希望对您有所帮助。

借助DateComponents在Date中设置小时和分钟，然后分配datePicker的最小值和最大值

let startHour: Int = 6
let endHour: Int = 23
let date1: NSDate = NSDate()
let gregorian: NSCalendar = NSCalendar(calendarIdentifier: NSCalendar.Identifier.gregorian)!
var components: DateComponents = gregorian.components(([.day, .month, .year]), from: date1 as Date)
components.hour = startHour
components.minute = 0
components.second = 0
let startDate: Date = gregorian.date(from: components)!
components.hour = endHour
components.minute = 0
components.second = 0
let endDate: Date = gregorian.date(from: components)!
timePicker.datePickerMode = .Time
timePicker.minimumDate = startDate
timePicker.maximumDate = endDate
timePicker.setDate(startDate, animated: true)
timePicker.reloadInputViews()