arrays - 如何根据行中的值对 Swift 中的二维数组列进行排序？

Question

如何根据其中一行中的值对二维数组进行排序？

let array = [["X", "Y",   1,  2,  3,  4,  5],
             ["V", "W", "A","B","C","D","E"]
]

let sorted = [["X", "Y",   5,  4,  3,  2,  1],
              ["V", "W", "E","D","C","B","A"]
    ]

swift Array.sort({e1, e2 in e1 < e2})传入行元素，而不是列元素。

更糟糕的是，该行中的前两列不得排序。

请记住，第 2 行必须根据第 1 行的顺序重新排列。因此，假设我们按第 0 行排序并忽略第 1 2 列

[["X", "Y",   1,  2,  3,  4,  5],
 ["V", "W", "E","B","A","D","F"]]

应该变成

[["X", "Y",   5,  4,  3,  2,  1],
 ["V", "W", "F","D","A","B","E"]]

Answer 1

首先映射数组元素并从子数组中拆分前 2 个元素以跳过排序。现在使用开关模式匹配对剩余元素进行排序。然后将排序后的数组与前 2 个元素连接起来。

let array = [["X", "Y",   1,  2,  3,  4,  5],
             ["V", "W", "A","B","C","D","E"]]

let sorted = array.map { $0[..<2] + $0[2...].sorted(by: {
    switch ($0,$1) {
    case (let a as Int, let b as Int): return a > b
    case (let a as String, let b as String): return a > b
    case (let a as Date, let b as Date): return a > b
    case (_, _): return false
    }
})}.map { Array($0) }
print(sorted)

[["X", "Y", 5, 4, 3, 2, 1], ["V", "W", "E", "D", "C", "B", "A"]]