json - 如何在 Swift/Xcode 中从 Google Places API 解析 JSON "nearby search response"

Question

Google map API 运行良好，我收到了适当的 JSON 响应。但是，我在解析错综复杂的 JSON 响应以获得我需要的特定信息(例如位置名称)时遇到了麻烦。我基本上浏览了所有我能找到的 YouTube 教程和在线帖子，但没有任何帮助。我已包含我正在使用的当前代码以及概述我收到的 JSON 响应的文档的链接。任何帮助将不胜感激!

https://developers.google.com/places/web-service/search#nearby-search-and-text-search-responses

func nearbyLocations(latitude: Double, longitude: Double) {


    let jsonUrlString = "https://maps.googleapis.com/maps/api/place/nearbysearch/json?location=\(latitude),\(longitude)&radius=25&key=..."

    guard let url = URL(string: jsonUrlString) else { return }

    URLSession.shared.dataTask(with: url) { (data, respone, err) in

        guard let data = data else { return }

        do {
            guard let json = try JSONSerialization.jsonObject(with: data, options: .mutableContainers) as? [String: Any] else { return }
            print(json)
        } catch let jsonErr {
            print("json error:", jsonErr)
        }

    }.resume()
}

Answer 1

您可以像这样解析正常:

if let results = json["results"] as! [[String:Any]], let firstResult = results.first {
    let geometry = firstResult["geometry"] as! [String:Any]
    let location = geometry["location"] as! [String:Any]
    let lat = location["lat"] as! Double
    let lng = location["lng"] as! Double
}