javascript数组在另一个数组中重复

Question

假设我在 javascript 中有这个数组

ar = ['C241C12A-45FD-40FF-B26E-B879107E584D||20',
      'AB1BB99D-4396-415A-A5D8-1BEF3E0149CE||33',
      'ADE54113-53D1-4F26-A01C-48EBE37E3CE8||85',
      'DB500FD1-5988-4202-A4AA-727AC29AC67A||85',
      '8A8EAB5A-E0D2-4AA8-96A0-42686FF5EB0C||10',
      '50C29E8A-16C7-4FC2-A186-C3D65F23C627||200',
      '70C79BBB-14C7-4F34-346B-CSSSDFVFZZZ7||200'
    ];

有没有办法得到这样的数组

newarray1 = [
      'ADE54113-53D1-4F26-A01C-48EBE37E3CE8||85',
      'DB500FD1-5988-4202-A4AA-727AC29AC67A||85'
      ];
 newarray2 = [
      '50C29E8A-16C7-4FC2-A186-C3D65F23C627||200',
      '70C79BBB-14C7-4F34-346B-CSSSDFVFZZZ7||200'
      ];

管道符号后面的重复值，获取该值并基于该值形成一个新数组

Answer 1

var arraysByKey = {};
for (var i=0; i<ar.length; i++) {
    var key = ar[i].split("||")[1];
    if (key in arraysByKey)
        arraysByKey[key].push( ar[i] );
    else
        arraysByKey[key] = [ ar[i] ];
}

结果 (arraysByKey) 将如下所示:

{
    "10": [
        "8A8EAB5A-E0D2-4AA8-96A0-42686FF5EB0C||10"
    ],
    "20": [
        "C241C12A-45FD-40FF-B26E-B879107E584D||20"
    ],
    "33": [
        "AB1BB99D-4396-415A-A5D8-1BEF3E0149CE||33"
    ],
    "85": [
        "ADE54113-53D1-4F26-A01C-48EBE37E3CE8||85",
        "DB500FD1-5988-4202-A4AA-727AC29AC67A||85"
    ],
    "200": [
        "50C29E8A-16C7-4FC2-A186-C3D65F23C627||200",
        "70C79BBB-14C7-4F34-346B-CSSSDFVFZZZ7||200"
    ]
}

如果您只想要存在“重复值”的数组，只需过滤结果:

for (var key in arraysByKey)
    if (arraysByKey[key].length < 2)
        delete arraysByKey[key];