Java - 如何将值从 switch 语句插入到数组

Question

我正在尝试创建一个程序，从一副 52 张牌中分出两张牌。到目前为止，我已经使用 switch 语句将卡片值分配给一个数字，例如黑桃 A = 0，梅花七 = 26。但是，为了拥有两张卡片，它们必须是独一无二的，我不知道该怎么做。

import java.lang.Object;
import java.util.Scanner;
import java.util.Random;

public class Deck {

public static void main(String[] args) {

    Random rnd = new Random();
    int cardNumber = rnd.nextInt(52);
    String toCard = null;
    switch (cardNumber){
    case 0: toCard = "Ace of Spades";
            break;
    case 1: toCard = "Ace of Hearts";
            break;      
    case 2: toCard = "Ace of Clubs";
            break;
    case 3: toCard = "Ace of Diamonds";
            break;      
    case 4: toCard = "Two of Spades";
            break;
    case 5: toCard = "Two of Hearts";
            break;      
    case 6: toCard = "Two of Clubs";
            break;      
    case 7: toCard = "Two of Diamonds";
            break;      
    case 8: toCard = "Three of Spades";
            break;      
    case 9: toCard = "Three of Hearts";
            break;      
    case 10: toCard = "Three of Clubs";
            break;      
    case 11: toCard = "Three of Diamonds";
            break;  
    case 12: toCard = "Four of Spades";
            break;      
    case 13: toCard = "Four of Hearts";
            break;      
    case 14: toCard = "Four of Clubs";
            break;      
    case 15: toCard = "Four of Diamonds";
            break;  
    case 16: toCard = "Five of Spades";
            break;      
    case 17: toCard = "Five of Hearts";
            break;      
    case 18: toCard = "Five of Clubs";
            break;      
    case 19: toCard = "Five of Diamonds";
            break;
    case 20: toCard = "Six of Spades";
            break;      
    case 21: toCard = "Six of Hearts";
            break;      
    case 22: toCard = "Six of Clubs";
            break;      
    case 23: toCard = "Six of Diamonds";
            break;
    case 24: toCard = "Seven of Spades";
            break;      
    case 25: toCard = "Seven of Hearts";
            break;      
    case 26: toCard = "Seven of Clubs";
            break;      
    case 27: toCard = "Seven of Diamonds";
            break;
    case 28: toCard = "Eight of Spades";
            break;      
    case 29: toCard = "Eight of Hearts";
            break;      
    case 30: toCard = "Eight of Clubs";
            break;      
    case 31: toCard = "Eight of Diamonds";
            break;
    case 32: toCard = "Nine of Spades";
            break;      
    case 33: toCard = "Nine of Hearts";
            break;      
    case 34: toCard = "Nine of Clubs";
            break;      
    case 35: toCard = "Nine of Diamonds";
            break;
    case 36: toCard = "Ten of Spades";
            break;      
    case 37: toCard = "Ten of Hearts";
            break;      
    case 38: toCard = "Ten of Clubs";
            break;      
    case 39: toCard = "Ten of Diamonds";
            break;
    case 40: toCard = "Jack of Spades";
            break;      
    case 41: toCard = "Jack of Hearts";
            break;      
    case 42: toCard = "Jack of Clubs";
            break;      
    case 43: toCard = "Jack of Diamonds";
            break;
    case 44: toCard = "Queen of Spades";
            break;      
    case 45: toCard = "Queen of Hearts";
            break;      
    case 46: toCard = "Queen of Clubs";
            break;      
    case 47: toCard = "Queen of Diamonds";
            break;
    case 48: toCard = "King of Spades";
            break;      
    case 49: toCard = "King of Hearts";
            break;      
    case 50: toCard = "King of Clubs";
            break;      
    case 51: toCard = "King of Diamonds";
            break;
    }


System.out.println(cardNumber + " " + toCard);

}

}

我知道可能有许多更有效的方法来解决这个问题，但总体而言，我对编码还比较陌生。我想将每个案例分配给数组中的一个索引，这样我就可以调用 cardArray[0] 并返回黑桃 A，并最终从 cardArray 调用两个随机数并让它们成为唯一的卡片。

感谢任何帮助。

Answer 1

为了给玩家发两张独特的牌，你的职业设计应该类似于这样:

Player 应该有一组卡片。

public class Player {
    private String[] cards;

    public String[] getCards() {
        return cards;
    }

    public void setCards(String[] cards) {
        this.cards = cards;
    }

    @Override
    public String toString() {
        return "Player [cards=" + Arrays.toString(cards) + "]";
    }
}

CardDealer 应该有一副纸牌和一个 deal(Player... players) 方法来向给定的玩家发牌。

public class CardDealer {
    private static Random rand;
    private static final String[] DECK = { "Ace of Spades",
            "Ace of Hearts",
            "Ace of Clubs",
            "Ace of Diamonds",
            "Two of Spades",
            "Two of Hearts",
            "Two of Clubs",
            "Two of Diamonds",
            "Three of Spades",
            //etc.
    };
    //Use a java.util.Random object to generate random numbers.
    public CardDealer(){
        rand = new Random();
    }
    /**
      * This method accepts variable number of players
      * and for each player, it picks up two unique cards
      * from the deck, creates an array of those two cards
      * and assigns that array to the players
      */
    public void deal(Player... players){
        for(Player eachPlayer : players){
            // Create an array of 2 cards for each player
            String[] cards = new String[2];
            // Pick first card randomly from deck.
            int cardIndex1 = rand.nextInt(52);
            String card1 = DECK[cardIndex1];

            // Pick second card randomly from deck
            int cardIndex2 = rand.nextInt(52);
            // If the second picked index is equal to first, pick again
            while(cardIndex1 == cardIndex2){
                cardIndex2 = rand.nextInt(52);
            }
            String card2 = DECK[cardIndex2];

            //Give each player his cards.
            cards[0] = card1;
            cards[1] = card2;

            eachPlayer.setCards(cards);
        }
    }
}

现在，如果你运行这样的测试:

        CardDealer dealer = new CardDealer();
        Player sam = new Player();
        Player joe = new Player();

        dealer.deal(sam,joe);

        System.out.println("Sam -> " + sam);
        System.out.println("Joe -> " + joe);

它应该产生这样的结果:

Sam -> Player [cards=[Ten of Spades, Two of Spades]]
Joe -> Player [cards=[Two of Diamonds, King of Hearts]]

我希望这能给你一些继续下去的想法。