gpt4 book ai didi

java - 如何将 HashMap 值获取到 Android 中 Listview 的 CustomlistAdapter

转载 作者:行者123 更新时间:2023-11-30 10:29:39 24 4
gpt4 key购买 nike

我尝试从我的 MainActivity 获取数据到我的 Customlist Activity 以在 ListView 中显示数据。不幸的是我找不到我的错误。这是我的 MainActivity:

public class Locations extends Activity{
private String TAG = Locations.class.getSimpleName();

private ProgressDialog pDialog;


// URL to get contacts JSON
private static String url = "";

ArrayList<HashMap<String, String>> contactList;

@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);

contactList = new ArrayList<>();

}

/**
* Async task class to get json by making HTTP call
*/
private class GetContacts extends AsyncTask<Void, Void, Void> {

@Override
protected void onPreExecute() {
super.onPreExecute();
// Showing progress dialog
pDialog = new ProgressDialog(Locations.this);
pDialog.setMessage("Please wait...");
pDialog.setCancelable(false);
pDialog.show();

}

@Override
protected Void doInBackground(Void... arg0) {
HttpHandler sh = new HttpHandler();

// Making a request to url and getting response
String jsonStr = sh.makeServiceCall(url);

Log.e(TAG, "Response from url: " + jsonStr);

if (jsonStr != null) {
try {
JSONArray contacts = new JSONArray(jsonStr);

// Getting JSON Array node


// looping through All Contacts
for (int i = 0; i < contacts.length(); i++) {
JSONObject c = contacts.getJSONObject(i);

String id = c.getString("id");
String name = c.getString("name");
String imageurl = c.getString("imageurl");
// tmp hash map for single contact
HashMap<String, String> contact = new HashMap<>();

// adding each child node to HashMap key => value
contact.put("id", id);
contact.put("name", name);
contact.put("imageurl",imageurl);

// adding contact to contact list
contactList.add(contact);
}
} catch (final JSONException e) {
Log.e(TAG, "Json parsing error: " + e.getMessage());
runOnUiThread(new Runnable() {
@Override
public void run() {
Toast.makeText(getApplicationContext(),
"Json parsing error: " + e.getMessage(),
Toast.LENGTH_LONG)
.show();
}
});

}
} else {
Log.e(TAG, "Couldn't get json from server.");
runOnUiThread(new Runnable() {
@Override
public void run() {
Toast.makeText(getApplicationContext(),
"Couldn't get json from server. Check LogCat for possible errors!",
Toast.LENGTH_LONG)
.show();
}
});

}

return null;
}

@Override
protected void onPostExecute(Void result) {
super.onPostExecute(result);
// Dismiss the progress dialog
if (pDialog.isShowing())
pDialog.dismiss();
/**3
* Updating parsed JSON data into ListView
* */

Customlist adapter = new
Customlist(Locations.this, contactList);
list=(ListView)findViewById(R.id.lv);
list.setAdapter(adapter);


}

}
}

这是我的 CustomlistActivity:

public class Customlist extends ArrayAdapter<String> {
private final Activity context;
private final HashMap<String, String> contactlist;
public Customlist(Activity context, ArrayList<HashMap<String, String>> contactlist) {
super(context, R.layout.model, (List<String>) contactlist);
this.context = context;
this.contactlist= contactlist;


}
@Override
public View getView(int position, View view, ViewGroup parent) {
LayoutInflater inflater = context.getLayoutInflater();
View rowView= inflater.inflate(R.layout.model, null, true);
TextView txtTitle = (TextView) rowView.findViewById(R.id.namelist);

ImageView imageView = (ImageView) rowView.findViewById(R.id.imagelist);


return rowView;
}
}

最佳答案

1.当你经过HashMap , 所以扩展 Customlist来自 ArrayAdapter<HashMap<String, String>>而不是 ArrayAdapter<String> .

2.更新constructor如下:

    public Customlist(Context context, ArrayList<HashMap<String, String>> contactlist) {
super(context, R.layout.model, contactlist);
this.context = context;
this.contactlist= contactlist;
}

3. 在你的getView()方法,得到HashMap来自 List得到 id , nameimageurl如下:

// Contact
HashMap<String, String> contact = contactlist.get(position);

String id = contact.get("id");
String name = contact.get("name");
String imageurl = contact.get("imageurl");

这是更新的 Customlist适配器:

public class Customlist extends ArrayAdapter<HashMap<String, String>> {
private Context context;
private ArrayList<HashMap<String, String> contactlist;

public Customlist(Context context, ArrayList<HashMap<String, String>> contactlist) {
super(context, R.layout.model, contactlist);
this.context = context;
this.contactlist= contactlist;
}


@Override
public View getView(int position, View view, ViewGroup parent) {
LayoutInflater inflater = context.getLayoutInflater();
View rowView= inflater.inflate(R.layout.model, null, true);
TextView txtTitle = (TextView) rowView.findViewById(R.id.namelist);
ImageView imageView = (ImageView) rowView.findViewById(R.id.imagelist);


// Contact
HashMap<String, String> contact = contactlist.get(position);

String id = contact.get("id");
String name = contact.get("name");
String imageurl = contact.get("imageurl");

// Do something with value id, name and imageurl

return rowView;
}

}

希望对你有帮助~

关于java - 如何将 HashMap 值获取到 Android 中 Listview 的 CustomlistAdapter,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/43956238/

24 4 0
Copyright 2021 - 2024 cfsdn All Rights Reserved 蜀ICP备2022000587号
广告合作:1813099741@qq.com 6ren.com