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java - 如何在单击按钮时重新绘制 JPanel?

转载 作者:行者123 更新时间:2023-11-30 10:27:47 25 4
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我是 swing 的新手,目前正在尝试制作一个绘图程序。这是我目前所拥有的。

这是主类:

import java.util.*;
import static java.lang.System.*;
import java.awt.*;
import javax.swing.*;
public class DrawingBoard {
static JPanel buttonPanel;
static JPanel drawingPanel;
public static void main(String[] args) {
JFrame window = new JFrame();
window.setSize(500, 500);
window.setTitle("Drawing Board");
window.getContentPane().setBackground(Color.black);
window.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
window.setLayout(new FlowLayout());

buttonPanel = new JPanel();
buttonPanel.setLayout(new BoxLayout(buttonPanel, BoxLayout.Y_AXIS));
buttonPanel.setPreferredSize(new Dimension(80, 500));
buttonPanel.setBackground(Color.lightGray);
DrawingComponent drawingComp = new DrawingComponent();
drawingComp.setButtonPanel();
window.getContentPane().add(buttonPanel);

drawingPanel = new JPanel();
drawingPanel.setPreferredSize(new Dimension(420, 500));
drawingPanel.setBackground(Color.white);
drawingPanel.add(drawingComp);
window.getContentPane().add(drawingPanel);

window.pack();
window.setVisible(true);
}
}

这是绘图类:

import java.awt.*;
import java.awt.event.ActionEvent;
import java.awt.event.ActionListener;
import javax.swing.*;
import static java.lang.System.*;
public class DrawingComponent extends JComponent implements ActionListener {
private static final long serialVersionUID = 1L;
public void paint(Graphics g) {
super.paintComponents(g);
g.setColor(Color.red);
g.fillRect(50, 50, 150, 150);
}
public void setButtonPanel() {
JLabel colors = new JLabel("Colors", SwingConstants.CENTER);
DrawingBoard.buttonPanel.add(colors);

JButton red = new JButton("Red");
DrawingBoard.buttonPanel.add(red);
red.addActionListener(this);

JButton blue = new JButton("Blue");
DrawingBoard.buttonPanel.add(blue);
blue.addActionListener(this);

JButton green = new JButton("Green");
DrawingBoard.buttonPanel.add(green);
green.addActionListener(this);

JButton yellow = new JButton("Yellow");
DrawingBoard.buttonPanel.add(yellow);
yellow.addActionListener(this);

JButton orange = new JButton("Orange");
DrawingBoard.buttonPanel.add(orange);
orange.addActionListener(this);

JButton pink = new JButton("Pink");
DrawingBoard.buttonPanel.add(pink);
pink.addActionListener(this);

JButton purple = new JButton("Purple");
DrawingBoard.buttonPanel.add(purple);
purple.addActionListener(this);

JButton black = new JButton("Black");
DrawingBoard.buttonPanel.add(black);
black.addActionListener(this);

JLabel tools = new JLabel("Tools", SwingConstants.CENTER);
DrawingBoard.buttonPanel.add(tools);

JButton erase = new JButton("Erase");
DrawingBoard.buttonPanel.add(erase);
erase.addActionListener(this);

JButton drawLine = new JButton("Lines");
DrawingBoard.buttonPanel.add(drawLine);
drawLine.addActionListener(this);

JButton clear = new JButton("Clear");
DrawingBoard.buttonPanel.add(clear);
clear.addActionListener(this);
}
public void actionPerformed(ActionEvent e) {
if(e.getActionCommand().equals("Red")) {
out.println("red");
repaint();
}
else if(e.getActionCommand().equals("Blue")) {
out.println("blue");
repaint();
}
else if(e.getActionCommand().equals("Green")) {
out.println("green");
repaint();
}
else if(e.getActionCommand().equals("Yellow")) {
out.println("yellow");
repaint();
}
else if(e.getActionCommand().equals("Orange")) {
out.println("orange");
repaint();
}
else if(e.getActionCommand().equals("Pink")) {
out.println("pink");
repaint();
}
else if(e.getActionCommand().equals("Purple")) {
out.println("purple");
repaint();
}
else if(e.getActionCommand().equals("Black")) {
out.println("black");
repaint();
}
else if(e.getActionCommand().equals("Erase")) {
out.println("erase");
repaint();
}
else if(e.getActionCommand().equals("Lines")) {
out.println("lines");
repaint();
}
else if(e.getActionCommand().equals("Clear")) {
out.println("clear");
repaint();
}
}
}

这是输出图片的链接。 /image/GEwga.png

现在,我只想让绘图板在单击按钮时显示某种图形。其他一切都很好,但是当我单击任何按钮时,绘图面板(白色区域)中没有像预期的那样显示任何图形。按钮的 println 语句仍会执行,但 repaint() 只是直接不起作用。我如何做到这一点,以便当我单击一个按钮时调用 paintComponent 方法并在 drawingPanel(窗口的白色区域)上显示一个图形?我已经在这个问题上停留了很长一段时间,所以非常感谢帮助。

最佳答案

drawingPanel = new JPanel(); 更改为 `drawingPanel = new JPanel(new BorderLayout());

DrawingComponent 的默认首选大小为 0x0,因此当您将它添加到 JPanel(使用 FlowLayout 默认情况下),它的大小将变为 0x0,因此您不会看到任何绘制的内容

然后改变...

public void paint(Graphics g) {
super.paintComponents(g);
g.setColor(Color.red);
g.fillRect(50, 50, 150, 150);
}

为了...

@Override
protected void paintComponent(Graphics g) {
System.out.println("Hello");
super.paintComponent(g);
g.setColor(Color.red);
g.fillRect(10, 10, 150, 150);
}

关于你的代码还有很多其他的东西让我害怕,但我没有时间去解决所有的问题

关于java - 如何在单击按钮时重新绘制 JPanel?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/45096467/

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