java - 如何在 Maven 中继承构建选项？

Question

我有一个 super pom:

<resources>
  <resource>
    <filtering>true</filtering>
    <directory>(path to my project)\src\main\resources</directory>
    <includes>
      <include>**/application*.yml</include>
      <include>**/application*.properties</include>
    </includes>
  </resource>
  <resource>
    <directory>(path to my project)\src\main\resources</directory>
    <excludes>
      <exclude>**/application*.yml</exclude>
      <exclude>**/application*.properties</exclude>
    </excludes>
  </resource>
</resources>

案例是:

当我将下面的代码放入项目的 pom 中时，会自动覆盖 super pom 配置:

<build>
    <resources>
        <resource>
            <filtering>true</filtering>
            <directory>my-project/src/main/resources</directory>
            <excludes>
                <exclude>*.yml</exclude>
            </excludes>
        </resource>
    </resources>
</build>

如何将 super pom 配置和“concat”与我的项目 pom 一起使用:

<resources>
  <resource>
    <filtering>true</filtering>
    <directory>(path to my project)\src\main\resources</directory>
    <includes>
      <include>**/application*.yml</include>
      <include>**/application*.properties</include>
    </includes>
  </resource>
  <resource>
    <directory>(path to my project)\src\main\resources</directory>
    <excludes>
      <exclude>**/application*.yml</exclude>
      <exclude>*.yml</exclude> <!-- my project pom config -->
      <exclude>**/application*.properties</exclude>
    </excludes>
  </resource>
</resources>

Answer 1

当我学习 Maven 时，我也注意到子模块中定义的任何资源都优先于父 POM 中的资源。使它们按照描述进行“连接”的唯一方法是在子项中重复父项配置，然后像您一样添加新选项。这是 Maven 3.2，不确定以后的版本是否有更好的处理方法。 Plugins have an explicit way to say 'merge' ，请参阅 combine.children 和相关属性。