swift - Parse 和 Swift 上的关系查询

Question

我正在尝试获取与类相关的对象。

以下是我的查询:

var user = PFUser.currentUser()
println("PERSON\(user)")
var relation = user!.relationForKey("followingThings")
var queryTeste = relation.query()
queryTeste?.findObjectsInBackgroundWithBlock({ (object: [AnyObject]?, error: NSError?) -> Void in
    println("OBJECTS FROM RELATIONAL QUERY\(object)")
})

如果您查看输出，我可以检索我的关系对象，但是...我在检索它们之前收到错误。

我尝试了不同的组合来摆脱它，但没有成功。此外，这里的大多数问题都是关于 Objective C 和 sintaxe 的，方法也略有不同。

关于可能导致错误的原因有什么想法吗？

PERSONOptional( { email = "myemail@gmail.com"; emailVerified = 1; followingThings = " Things>"; points = 10; username = Me; })

2015-08-31 19:16:32.161 App[30479:9376080] [Error]: field followingThings cannot be included because it is not a pointer to another object (Code: 102, Version: 1.8.0)

OBJECTS FROM RELATIONAL QUERYOptional([

Things: 0x7ff031a736c0, objectId: G29f9Wfqj5, localId: (null)> { description = Camping; searchKey = camping; usersFollowing = " _User>"; },

Things: 0x7ff031a76520, objectId: IPEg4G2Qec, localId: (null)> { description = "Animal Care"; searchKey = "animal care"; usersFollowing = " _User>"; },

Things: 0x7ff031a76120, objectId: Jg4oRjebKE, localId: (null)> { description = Bicycling; searchKey = bycicling; usersFollowing = " _User>"; },

Things: 0x7ff031a75810, objectId: TseQvlo6AL, localId: (null)> { description = Boating; searchKey = boating; usersFollowing = " _User>"; }])

Answer 1

对我来说就是这样

    var relation = currentUser.relationForKey("product")
                        relation.query()?.findObjectsInBackgroundWithBlock({

                            (let productResult, let error) -> Void in
                            //println("result:\(productResult!.count)")

                            if let result = productResult {
                                //println(result.count)
                                for product in result {
println(product)
}
}
}