java - 使用 Java 进行 Apache Flink CEP 模式检测

Question

我想做；
从 CEP 开始，使用映射结构中包含的任何数组列表元素，然后继续我已经开始的其余数组列表元素。
map 和图案结构:

final Map< Integer,ArrayList<String>> deger = new HashMap<Integer,ArrayList<String>>();
        deger.put(1,new ArrayList<String>(Arrays.asList("h:1","l:1","g:0")));
        deger.put(2,new ArrayList<String>(Arrays.asList("h:1","l:1","g:1")));
        deger.put(3,new ArrayList<String>(Arrays.asList("h:2","l:3","g:1")));
        deger.put(4,new ArrayList<String>(Arrays.asList("h:0","l:2","g:2")));

 for(int i=1;i<deger.size()+1;i++) {
            temp1.add(deger.get(i));
        }

Pattern<String,?> pattern = Pattern.<String>begin("start").where(
                new SimpleCondition<String>() {
//                    @Override
                    public boolean filter(String value) throws Exception {

                        for (ArrayList<String> aa: temp1){
                            for (String dd : aa)
                                if(value.equals(dd)){ 
                                    return true;
                                }
                        }
                        return false;
                    }
                }
        ).followedBy("middle").where(
                new SimpleCondition<String>() {
                    @Override
                    public boolean filter(String value) throws Exception {
                        return value.equals(temp1.get(1));
                    }
                }
        ).followedBy("end").where(
                new SimpleCondition<String>() {
                    @Override
                    public boolean filter(String value) throws Exception {
                        return value.equals(temp1.get(2));
                    }
                }
        );

我的目标是用 map 中的 arraylist 元素发出警告，但 arraylist 元素的顺序并不重要，因为其中有流。我想继续处理这个数组的其余元素，在那里我可以返回信息当我从这里的任何数组开始时，这个数组。例如:

Incoming data = "l:1","h:1","g:0"
my pattern = "h:1","l:1","g:0" 
Start -> l:1 find
Middle -> g:0 or h:1 | h:1 find
End -> g:0 find -> alarm

Answer 1

 public static  Integer temp1;
    public static  Map<Integer,ArrayList<String>> temp2 = new HashMap<>();     
final Map< Integer,ArrayList<String>> deger = new HashMap<>();
            deger.put(1,new ArrayList<>(Arrays.asList("h:1","g:1","s:0")));
            deger.put(2,new ArrayList<>(Arrays.asList("h:1","g:1","g:0")));
            deger.put(3,new ArrayList<>(Arrays.asList("h:1","c:0","g:0")));
            deger.put(4,new ArrayList<>(Arrays.asList("h:1","s:1","g:0")));


            Pattern<String,?> pattern = Pattern.<String>begin("start").where(
                    new SimpleCondition<String>() {
                        @Override
                        public boolean filter(String value) throws Exception {
                            flag = false;
                            for(Map.Entry<Integer, ArrayList<String>> entryStart : deger.entrySet()) {
                                if(entryStart.getValue().contains(value) && !temp2.containsKey(entryStart.getKey())){
                                        ArrayList<String> newList = new ArrayList<String>();
                                        newList.addAll(entryStart.getValue());
                                        newList.remove(value);
                                        temp2.put(entryStart.getKey(),newList);
                                        flag = true;
                                }
                            }
                            return flag;
                        }
                    }
            ).followedBy("middle").where(
                    new SimpleCondition<String>() {
                        @Override
                        public boolean filter(String middle) throws Exception {
                            flag = false;
                            for(Map.Entry<Integer, ArrayList<String>> entryMiddle : temp2.entrySet()) {
                                if(entryMiddle.getValue().contains(middle) && entryMiddle.getValue().size() == 2){
                                    ArrayList<String> newListMiddle = new ArrayList<String>();
                                    newListMiddle.addAll(entryMiddle.getValue());
                                    newListMiddle.remove(middle);
                                    temp2.put(entryMiddle.getKey(),newListMiddle);
                                    flag = true;
                                }
                            }
                            return flag;
                        }
                    }
            ).followedBy("end").where(
                    new SimpleCondition<String>() {
                        @Override
                        public boolean filter(String end) throws Exception {
                            flag = false;
                            for(Map.Entry<Integer, ArrayList<String>> entryEnd : temp2.entrySet()) {
                                if(entryEnd.getValue().contains(end) && entryEnd.getValue().size() == 1){
                                    flag = true;
                                    temp1 = entryEnd.getKey();
                                }
                            }
                            if (flag)
                                temp2.remove(temp1);
                            return flag;
                        }
                    }
            );

            PatternStream<String> patternStream = CEP.pattern(stream_itemset_ham,pattern);

            DataStream<String> result = patternStream.select(
                    new PatternSelectFunction<String, String>() {
                        @Override
                        public String select(Map<String, List<String>> map) throws Exception {
                            ArrayList<String> NewList= new ArrayList<>();
                            NewList.addAll(deger.get(temp1));
                            String found = "Found";
                            for (String list_element : NewList)
                                found += " " + list_element ;
                            return found;
                        }
                    }
            );
            result.print();

从你的问题中我了解到可以提供这种解决方案。