javascript - 如何在 ecmascript 6 的 warriorjs 游戏中定义方法？

Question

我正在使用 warriorjs 学习 nodejs游戏。它给我一个简单的类:

class Player {
    playTurn(warrior) {
    }
}
global.Player = Player;

所以我想为 Player 类创建一个方法。例如:

class Player {
    playTurn(warrior) {
        foo();
    }

    playTurn(warrior) {
        foo();
    }

    foo() {}
}
global.Player = Player;

我认为这是在 js 中创建方法的方法，但它给出了错误:

undefined:25
      foo();
      ^
ReferenceError: foo is not defined
    at Player.playTurn (eval at loadPlayer (/usr/lib64/node_modules/warriorjs/lib/Level.js:155:94), <anonymous>:25:7)
    at Warrior.playTurn (/usr/lib64/node_modules/warriorjs/lib/units/Warrior.js:38:24)
    at Warrior.prepareTurn (/usr/lib64/node_modules/warriorjs/lib/units/Base.js:280:12)
    at /usr/lib64/node_modules/warriorjs/lib/Level.js:177:23
    at Array.forEach (native)
    at Level.play (/usr/lib64/node_modules/warriorjs/lib/Level.js:176:36)
    at Game.playCurrentLevel (/usr/lib64/node_modules/warriorjs/lib/Game.js:130:30)
    at Game.playNormalMode (/usr/lib64/node_modules/warriorjs/lib/Game.js:120:16)
    at Game.start (/usr/lib64/node_modules/warriorjs/lib/Game.js:70:14)
    at Runner.run (/usr/lib64/node_modules/warriorjs/lib/Runner.js:42:18)

谁能帮我弄清楚？

Answer 1

使用this.，因为.foo是Player的方法，不是全局函数

playTurn(warrior) {
  this.foo();
}

如果你想在没有.this的情况下调用foo，你需要添加foo函数，像这样

function foo() {

} 

class Player {
    playTurn(warrior) {
        foo();
    }

    playTurn(warrior) {
        foo();
    }
}

global.Player = Player;