java - 在 Scala 中使用正则表达式从服务器日志字符串中提取路径

Question

我有一些如下的日志

endeavor.fujitsu.co.jp - - [10/Jul/1995:00:00:15 -0400] "GET /images/ HTTP/1.0" 200 17688                                   
ad13-022.compuserve.com - - [10/Jul/1995:00:00:15 -0400] "GET /history/gemini/gemini-spacecraft.txt HTTP/1.0" 200 651       
pm2-15.magicnet.net - - [10/Jul/1995:00:00:15 -0400] "GET /images/launch-logo.gif HTTP/1.0" 200 1713                        
204.239.199.40 - - [10/Jul/1995:00:00:16 -0400] "GET /shuttle/missions/sts-71/images/KSC-95EC-0613.gif HTTP/1.0" 200 45970  
pm1-4.tricon.net - - [10/Jul/1995:00:00:17 -0400] "GET /images/WORLD-logosmall.gif HTTP/1.0" 200 669                        
scorpio.digex.net - - [10/Jul/1995:00:00:19 -0400] "GET /history/mercury/mr-3/mr-3.html HTTP/1.0" 200 1124

我需要从上述日志中提取路径。这是我试过的代码

val pattern = "\\s+([^\\s]+)\\s+HTTP".r
val match = pattern.findFirstIn(log)

这是我得到的输出。

/images/ HTTP
/history/gemini/gemini-spacecraft.txt HTTP
/images/launch-logo.gif HTTP
/shuttle/missions/sts-71/images/KSC-95EC-0613.gif HTTP
/images/WORLD-logosmall.gif HTTP
/history/mercury/mr-3/mr-3.html HTTP

如何去除上述路径中的 HTTP？

Answer 1

你的比赛在第一个捕获组中，

或者你可以使用积极的前瞻

\\s+[^\\s]+(?=\\s+HTTP)

Demo