regex - Swift 中特定字符后用空格分隔值

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嗨，我有一个值是

Blockquote 1 1:0.0644343 1 1:0.0309334 1 1:0.0261616 Blockquote

我想用空格分隔值，但在某些字符之后得到这样的结果..有没有可能的解决方案。我知道我们可以用正则表达式来做

Blockquote "1 1:0.0644343" "1 1:0.0309334" "1 1:0.0261616" Blockquote

Answer 1

我认为正则表达式是这里的完美工具:

var str = "Blockquote 1 1:0.0644343 1 1:0.0309334 1 1:0.0261616 Blockquote"

let regex = try! NSRegularExpression(pattern: "(\\d \\d:[\\.0-9]+)", options: [])
let matches = regex.matchesInString(str, options: [], range: NSMakeRange(0, str.characters.count))

for m in matches.reverse() {
    let range = m.rangeAtIndex(1)
    let startIndex = str.startIndex.advancedBy(range.location)
    let endindex = startIndex.advancedBy(range.length)
    let value = str[startIndex..<endindex]

    str.replaceRange(startIndex..<endindex, with: "\"\(str[startIndex..<endindex])\"")
}

print(str)