python - 如何在Python中逐行遍历表格的列并将其放入列表中

Question

列表1

0, 19.2, 20.3, 21.3, 23.5, 24.6, 25.2, 25.4, 26.2, 26.3, 26.4, 8655, Light
26.2, 25.7, 25.2, 25.3, 22.3, 21.2, 20, 19.2, 19.1, 0, 0, 8655 , Light
0, 0, 54.2, 56.3, 62.3, 63.3, 65.2, 65.3, 65.3, 65.4, 65.4, 8483, Fan
65.4, 65.2, 65.1, 64.2, 63.2, 62.5, 61.3, 56.4, 53.8, 53.2, 0, 8483, Fan
32.3, 33.6, 34.2, 36.3, 34.1, 32.3, 33.6, 33.5, 33.2, 33.3, 33.3, 8470, Fridge
32.3, 34.6, 35.2, 36.3, 34.1, 32.1, 33.6, 33.3, 33.2, 33.3, 33.3, 8470, Fridge
0, 129.3, 2235.6, 2236.2, 2235.5, 2232.3, 2235.6, 2234.2, 2235.2, 2235.4, 2235.6, 8903, WaterHeater
2236.4, 2235.2, 2235.6, 2236.2, 2235.5, 2232.3, 2235.6, 2234.2, 1992.5, 119.3, 0, 8903, WaterHeater

问题:如何编写程序，使其逐行遍历列表并追加到列表中(将用于 K 最近邻预测)

列表:[0、19.2、20.3、21.3、23.5、24.6、25.2、25.4、26.2、26.3、26.4、8655、浅色]

Such that it will be in a list after convert to 2D Array 
List:[[0],
     [19.2],
     [20.3],
     [21.3],
     [26.4],
     [Light]]

Answer 1

您可以使用以下代码。

l = [0, 19.2, 20.3, 21.3, 23.5, 24.6, 25.2, 25.4, 26.2, 26.3, 26.4, 8655, 'Light']

final_list=[]
for i in l:
    final_list.append([i])

如果您想迭代一个我认为是列表列表的表，请使用下面的代码。

l1 = [0, 19.2, 20.3, 21.3, 23.5, 24.6, 25.2, 25.4, 26.2, 26.3, 26.4, 8655, 'Light']
[26.2, 25.7, 25.2, 25.3, 22.3, 21.2, 20, 19.2, 19.1, 0, 0, 8655 , 'Light']
[0, 0, 54.2, 56.3, 62.3, 63.3, 65.2, 65.3, 65.3, 65.4, 65.4, 8483, 'Fan']
[65.4, 65.2, 65.1, 64.2, 63.2, 62.5, 61.3, 56.4, 53.8, 53.2, 0, 8483, 'Fan']
[32.3, 33.6, 34.2, 36.3, 34.1, 32.3, 33.6, 33.5, 33.2, 33.3, 33.3, 8470, 'Fridge']
[32.3, 34.6, 35.2, 36.3, 34.1, 32.1, 33.6, 33.3, 33.2, 33.3, 33.3, 8470, 'Fridge']
[0, 129.3, 2235.6, 2236.2, 2235.5, 2232.3, 2235.6, 2234.2, 2235.2, 2235.4, 2235.6, 8903, 'WaterHeater']
[2236.4, 2235.2, 2235.6, 2236.2, 2235.5, 2232.3, 2235.6, 2234.2, 1992.5, 119.3, 0, 8903, 'WaterHeater']

final_list=[]

for l in l1:
    for i in l:
        final_list.append([i])

您的结果将出现在 Final_list 中。