Java URL/HttpURLConnection 如何在发布时避免 InputStream？

Question

是否可以对某些 URL 执行 POST 方法请求并避免读取响应？

无论我多么努力地避免读取响应，除非我读取响应，否则数据似乎永远不会到达服务器。奇怪吗？

我真的没有必要阅读任何响应数据，因为我要做的就是发布数据..(无论如何响应总是空白的)

 URL postURL = new URL("http://www.example.com/test/");
 HttpURLConnection con = (HttpURLConnection) postURL.openConnection();
 con.setUseCaches(false);
 con.setDoOutput(true);
 con.setDoInput(false); //why even make this if it doesn't function?
 con.setRequestMethod("POST"); 

 //PrintWriter out = new PrintWriter(con.getOutputStream());
 OutputStream out = con.getOutputStream();
 byte[] /*String postStr*/ bPost = ("foo1="+URLEncoder.encode("bar1")+"&"+  
                       "foo2="+URLEncoder.encode("bar2")+"&"+   
                       "foo3="+URLEncoder.encode("bar3").getBytes();
 out.write(bPost);

 //out.println(postStr); // send to server
 out.flush();
 out.close();   // close outputstream
 //con.getInputStream().close(); //thought maybe this would help but no change.


 /*
 //If I uncomment this it will work.
 String inputLine="";   //Stores the line of text returned by the server
 String resultsPage=""; // Stores the complete HTML results page

 BufferedReader in = new BufferedReader(
             new InputStreamReader(con.getInputStream()));

 while ((inputLine = in.readLine()) != null)
       resultsPage+=inputLine;
 in.close();
 */

Answer 1

写入后调用 getResponseCode()。

这还将为您提供 404 作为响应代码，而不是 FileNotFoundException。