java - Java 中的什么正则表达式可以捕获并删除此模式？

Question

假设我有几行维基百科 XML 如下所示:

[[Image:ChicagoAnarchists.jpg|thumb|A sympathetic engraving by [[Walter Crane]] of the executed "Anarchists of Chicago" after the [[Haymarket affair]]. The Haymarket affair is generally considered the most significant event for the origin of international [[May Day]] observances]] In 1907, the [[International Anarchist Congress of Amsterdam]] gathered delegates from 14 different countries, among which important figures of the anarchist movement, including [[Errico Malatesta]]

我想删除以 [[Image:”开头并以“observances]] 结尾的行。可能还有其他几行带有方括号的文本，我不想进行贪婪搜索，否则它也可能会不小心删除其他方括号。

例如，如果我只是做了一个贪婪的 \\[\\[Image:.*\\]\\]，我相信它会删除最后一个右括号之前的所有内容(Ericco马拉泰斯塔)

是否有正则表达式可以让我更轻松地完成这项工作？

Answer 1

让我们看看...使用惰性重复而不是贪婪重复怎么样？

\[\[Image:.*?observances\]\]