python - 如何创建一个函数来传递 BeautifulSoup

Question

我正在尝试创建一个将内容传递给 beautiful soup 的函数，但我要么收到指示错误，要么不打印提供的 URL 中的文本。

from bs4 import BeautifulSoup
 import urllib.request
 def beautifulsoup(cont):
  url = "https://en.wikipedia.org/wiki/Machine_learning"
  content = urllib.request.urlopen(url)
  soup = BeautifulSoup(content)
print(soup.get_text())

我希望得到一个将内容传递给 beautiful soup 并打印出文本的函数。

Answer 1

这应该有效

import requests
from bs4 import BeautifulSoup

def read_content():  
    url = "https://en.wikipedia.org/wiki/Machine_learning"
    response = requests.get(url)
    html = response.content
    soup = BeautifulSoup(html)
    return soup.text


print(read_content())