javascript - 过滤 JSON 对象

Question

我正在从 XMLHttpRequest 中获取一个 JSON 对象，并且正在寻找一种解决方案来过滤 bt genre。如果未传递可过滤参数，我还需要一种返回所有结果(未过滤)的方法。

app.js(伪函数)

function filterObject(json, filterBy) {
  // filter through json
  // return item that matches filterBy
}

data.json

[{
  "date": {
    "dayOfWeek": "Thursday",
    "month": "Oct"
  },
  "location": "Bristol",
  "genre": "rock"
}, {
  "date": {
    "dayOfWeek": "Cardiff",
    "dayOfMonth": 13,
    "month": "Oct"
  },
  "location": "Manchester",
  "genre": "jazz"
}]

Answer 1

您可以使用 array#filter 根据 genre 值过滤您的 json。

var json = [{"date": {"dayOfWeek": "Thursday","month": "Oct"},"location": "Bristol","genre": "rock"}, {"date": {"dayOfWeek": "Cardiff","dayOfMonth": 13,"month": "Oct"},"location": "Manchester", "genre": "jazz"}];

function filterObject(json, filterBy) {
  return filterBy ? json.filter(o => o.genre === filterBy) : json;
}

console.log(filterObject(json,'jazz'));

console.log(filterObject(json));

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