javascript - 处理 jQuery.noConflict

Question

我继承了这样开头的脚本:

var $j = jQuery.noConflict();

但我不知道为什么要这样做。我知道我们正在尝试解决冲突，但我如何才能找到它正在尝试解决的冲突？

如果我们找不到真正的冲突，我们计划恢复到 $ 而不是 $j 并查看是否出现任何冲突。

Answer 1

根据 jQuery 文档

Many JavaScript libraries use $ as a function or variable name, just as jQuery does. In jQuery's case, $ is just an alias for jQuery, so all functionality is available without using $. If you need to use another JavaScript library alongside jQuery, return control of $ back to the other library with a call to $.noConflict(). Old references of $ are saved during jQuery initialization; noConflict() simply restores them.

If for some reason two versions of jQuery are loaded (which is notrecommended), calling $.noConflict( true ) from the second versionwill return the globally scoped jQuery variables to those of the firstversion.

Here is another link of docs that can explain very well

简单来说

var $j = jQuery.noConflict();

在此之后我们进入无冲突模式，因此我们现在可以使用 $j 而不是 $ 或 jQuery，并且该代码不会与以前版本的 Jquery 或使用 $ 或 jQuery 的库冲突