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javascript - 为什么我不能在此代码段中生成唯一对象数组?

转载 作者:行者123 更新时间:2023-11-30 09:26:04 25 4
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我有以下代码片段,我希望在其中过滤原始数组(过滤器)并获得唯一的过滤器数组。

我想我尝试了所有可能的方法,它(uniqueFilters 数组)仍然是相同的 11 成员原始数组。

怎么了?

我怎样才能确保这个数组实际上被过滤到其中只有几个独特的元素? (他们都来自同一个地方,都是一样的)

更新:- 答案成功解决了 js 代码中的问题。- 在实际的应用程序中,我还必须处理 typescript 才能使用建议的答案。所以也许会帮助某人:

let newUniqueFilters = Array.from(new Map(filters.map(f => [f._id, f] as [string, any])).values());

var filters = [{
"_id": "filter1",
"filterIndex": 1,
"filterLabel": "Blur",
"filterURL": "url(#filter1)",
"filterEffects": [{
"name": "feGaussianBlur",
"attributes": [{
"name": "stdDeviation",
"value": 5
}]
}]
}, {
"_id": "filter2",
"filterIndex": 2,
"filterLabel": "Shadow",
"filterURL": "url(#filter2)",
"filterEffects": [{
"name": "feOffset",
"attributes": [{
"name": "dx",
"value": 20
}, {
"name": "dy",
"value": 20
}, {
"name": "result",
"value": "offOut"
}, {
"name": "in",
"value": "SourceAlpha"
}]
}, {
"name": "feGaussianBlur",
"attributes": [{
"name": "stdDeviation",
"value": 7
}, {
"name": "in",
"value": "offOut"
}, {
"name": "result",
"value": "blurOut"
}]
}, {
"name": "feBlend",
"attributes": [{
"name": "mode",
"value": "normal"
}, {
"name": "in2",
"value": "blurOut"
}, {
"name": "in",
"value": "SourceGraphic"
}]
}]
}, {
"_id": "filter2",
"filterIndex": 2,
"filterLabel": "Shadow",
"filterURL": "url(#filter2)",
"filterEffects": [{
"name": "feOffset",
"attributes": [{
"name": "dx",
"value": 20
}, {
"name": "dy",
"value": 20
}, {
"name": "result",
"value": "offOut"
}, {
"name": "in",
"value": "SourceAlpha"
}]
}, {
"name": "feGaussianBlur",
"attributes": [{
"name": "stdDeviation",
"value": 7
}, {
"name": "in",
"value": "offOut"
}, {
"name": "result",
"value": "blurOut"
}]
}, {
"name": "feBlend",
"attributes": [{
"name": "mode",
"value": "normal"
}, {
"name": "in2",
"value": "blurOut"
}, {
"name": "in",
"value": "SourceGraphic"
}]
}]
}, {
"_id": "filter1",
"filterIndex": 1,
"filterLabel": "Blur",
"filterURL": "url(#filter1)",
"filterEffects": [{
"name": "feGaussianBlur",
"attributes": [{
"name": "stdDeviation",
"value": 5
}]
}]
}, {
"_id": "filter1",
"filterIndex": 1,
"filterLabel": "Blur",
"filterURL": "url(#filter1)",
"filterEffects": [{
"name": "feGaussianBlur",
"attributes": [{
"name": "stdDeviation",
"value": 5
}]
}]
}, {
"_id": "filter1",
"filterIndex": 1,
"filterLabel": "Blur",
"filterURL": "url(#filter1)",
"filterEffects": [{
"name": "feGaussianBlur",
"attributes": [{
"name": "stdDeviation",
"value": 5
}]
}]
}, {
"_id": "filter2",
"filterIndex": 2,
"filterLabel": "Shadow",
"filterURL": "url(#filter2)",
"filterEffects": [{
"name": "feOffset",
"attributes": [{
"name": "dx",
"value": 20
}, {
"name": "dy",
"value": 20
}, {
"name": "result",
"value": "offOut"
}, {
"name": "in",
"value": "SourceAlpha"
}]
}, {
"name": "feGaussianBlur",
"attributes": [{
"name": "stdDeviation",
"value": 7
}, {
"name": "in",
"value": "offOut"
}, {
"name": "result",
"value": "blurOut"
}]
}, {
"name": "feBlend",
"attributes": [{
"name": "mode",
"value": "normal"
}, {
"name": "in2",
"value": "blurOut"
}, {
"name": "in",
"value": "SourceGraphic"
}]
}]
}, {
"_id": "filter1",
"filterIndex": 1,
"filterLabel": "Blur",
"filterURL": "url(#filter1)",
"filterEffects": [{
"name": "feGaussianBlur",
"attributes": [{
"name": "stdDeviation",
"value": 5
}]
}]
}, {
"_id": "filter2",
"filterIndex": 2,
"filterLabel": "Shadow",
"filterURL": "url(#filter2)",
"filterEffects": [{
"name": "feOffset",
"attributes": [{
"name": "dx",
"value": 20
}, {
"name": "dy",
"value": 20
}, {
"name": "result",
"value": "offOut"
}, {
"name": "in",
"value": "SourceAlpha"
}]
}, {
"name": "feGaussianBlur",
"attributes": [{
"name": "stdDeviation",
"value": 7
}, {
"name": "in",
"value": "offOut"
}, {
"name": "result",
"value": "blurOut"
}]
}, {
"name": "feBlend",
"attributes": [{
"name": "mode",
"value": "normal"
}, {
"name": "in2",
"value": "blurOut"
}, {
"name": "in",
"value": "SourceGraphic"
}]
}]
}, {
"_id": "filter1",
"filterIndex": 1,
"filterLabel": "Blur",
"filterURL": "url(#filter1)",
"filterEffects": [{
"name": "feGaussianBlur",
"attributes": [{
"name": "stdDeviation",
"value": 5
}]
}]
}, {
"_id": "filter2",
"filterIndex": 2,
"filterLabel": "Shadow",
"filterURL": "url(#filter2)",
"filterEffects": [{
"name": "feOffset",
"attributes": [{
"name": "dx",
"value": 20
}, {
"name": "dy",
"value": 20
}, {
"name": "result",
"value": "offOut"
}, {
"name": "in",
"value": "SourceAlpha"
}]
}, {
"name": "feGaussianBlur",
"attributes": [{
"name": "stdDeviation",
"value": 7
}, {
"name": "in",
"value": "offOut"
}, {
"name": "result",
"value": "blurOut"
}]
}, {
"name": "feBlend",
"attributes": [{
"name": "mode",
"value": "normal"
}, {
"name": "in2",
"value": "blurOut"
}, {
"name": "in",
"value": "SourceGraphic"
}]
}]
}]

// first method:
var uniqueFilters = [];
for(let i = 0; i < filters.length; i++) {
if(uniqueFilters.indexOf(filters[i]) == -1){
uniqueFilters.push(filters[i])
}
}
console.log("first method")
console.log("original array length:" + filters.length)
console.log("unique array length:" + uniqueFilters.length)

// second method:
//var uniqueFilters = filters.filter(function(elem, index, self) {
// return index == self.indexOf(elem);
//});
//console.log("second method")
//console.log("original array length:" + filters.length)
//console.log("unique array length:" + uniqueFilters.length)

// suggested method 1:
var newUniqueFilters = Array.from(new Map(filters.map(f => [f._id, f])).values());
console.log(newUniqueFilters)

最佳答案

您可以使用 map :

filters = Array.from(new Map(filters.map(f => [f._id, f])).values());

这假设比较 _id 值就足够了,它唯一地标识过滤器。

请注意,比较对象本身(使用 indexOf 或类似方法)永远不会显示重复项,因为所有对象都是不同的引用(副本),即使它们看起来相同。一般来说,{} === {} 始终为 false。

关于javascript - 为什么我不能在此代码段中生成唯一对象数组?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/49054323/

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