javascript - Angular 项目 : How to get instance of secondary firebase app?

Question

在我的 Angular 应用程序中，我遇到了与提出以下问题的人相同的问题: Firebase kicks out current user

我希望能够在当前用户(= 创建新用户帐户的管理员)被踢出的情况下添加新用户帐户。

显然，这可以通过创建第二个身份验证引用并使用它来创建用户来实现(请参阅上面链接的问题的已批准答案):

var config = {apiKey: "apiKey",
    authDomain: "projectId.firebaseapp.com",
    databaseURL: "https://databaseName.firebaseio.com"};
var secondaryApp = firebase.initializeApp(config, "Secondary");

secondaryApp.auth().createUserWithEmailAndPassword(em, pwd).then(function(firebaseUser) {
    console.log("User " + firebaseUser.uid + " created successfully!");
    //I don't know if the next statement is necessary 
    secondaryApp.auth().signOut();
});

按照这个答案，我尝试了以下操作:

registerUser(authData: AuthData, participantId: string, role: string): Promise<any> {

        let config = {
            apiKey: "API-Key",
            authDomain: "myApp-a7211.firebaseapp.com",
            databaseURL: "https://myApp-a7211.firebaseio.com",
        };

        let secondaryApp = firebase.initializeApp(config, "Secondary");


        return secondaryApp.auth().createUserWithEmailAndPassword(authData.email, authData.password)
        .then(function(firebaseUser) {
            console.log("User " + firebaseUser + " created successfully!");

            secondaryApp.auth().signOut();
        });

}

问题是这只有效一次。之后，无法初始化辅助 firebaseApp，因为它已经被初始化。

所以我想，与其在 registerUser() 方法中初始化辅助应用程序，也许我应该做类似的事情(在文件 app.module.ts 中):

但是我如何在代码中引用辅助 firebaseApp？

---

更新:

按照 Frank van Puffelen 的建议回答，我做了以下事情:

1.) 在文件 app.module.ts 中:

2.) 在文件 auth.service.ts 中:

export class AuthService implements OnDestroy {

    private secondaryApp = firebase.app("Secondary");

    //other code

    registerUser(authData: AuthData): Promise<any> {

        return this.secondaryApp.auth().createUserWithEmailAndPassword(authData.email, authData.password)
        .then(function(firebaseUser) {
            console.log("User " + firebaseUser + " created successfully!");

            this.secondaryApp.auth().signOut();
        });

    }


    //other methods


 } 

但是，在尝试添加新用户时，我收到以下错误消息:

---

更新 2:

Frank van Puffelen 指出了我犯的一个愚蠢的错误:我注册该应用程序的名称与用于查找该应用程序备份的名称不匹配。更正此问题后，错误消息消失了。但是，当前用户在创建新帐户后仍然被踢出。

...最终起作用的是以下内容:

(文件 auth.service.ts:)

export class AuthService implements OnDestroy {

    //do not initialise the secondary app in app.module.ts but here:
    private config = {
        apiKey: "API-KEY",
        authDomain: "myApp-a7211.firebaseapp.com",
       databaseURL: "https://myApp-a7211.firebaseio.com",
    };
    private secondaryApp = firebase.initializeApp(this.config, "SecondaryApp");

    //other code

    registerUser(authData: AuthData): Promise<any> {

        return this.secondaryApp.auth().createUserWithEmailAndPassword(authData.email, authData.password)
        .then(function(firebaseUser) {
            console.log("User " + firebaseUser + " created successfully!");

            this.secondaryApp.auth().signOut();
        });

    }


    //other methods


 } 

Answer 1

您可以使 secondaryApp 成为全局的，然后在代码的其他地方引用它。所以像这样:

let secondaryApp;
registerUser(authData: AuthData, participantId: string, role: string): Promise<any> {

    let config = {
        apiKey: "AIzaSyAY1TWvQtK0tDQWmRzoouRNZzAnf15RG_A",
        authDomain: "myApp-a7211.firebaseapp.com",
        databaseURL: "https://myApp-a7211.firebaseio.com",
    };

   secondaryApp = firebase.initializeApp(config, "Secondary");

事实上，我会将辅助应用程序的整个配置拉出到全局范围内，因为它应该只运行一次。所以:

let config = {
    apiKey: "AIzaSyAY1TWvQtK0tDQWmRzoouRNZzAnf15RG_A",
    authDomain: "myApp-a7211.firebaseapp.com",
    databaseURL: "https://myApp-a7211.firebaseio.com",
};
let secondaryApp = firebase.initializeApp(config, "Secondary");
registerUser(authData: AuthData, participantId: string, role: string): Promise<any> {    
        return secondaryApp.auth().createUserWithEmailAndPassword(authData.email, authData.password)
        .then(function(firebaseUser) {
            ...
        });
}

您始终可以通过名称查找 FirebaseApp 实例。所以在你的情况下:

let secondaryApp = firebase.app("Secondary");