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python - tensorflow 逻辑回归

转载 作者:行者123 更新时间:2023-11-30 09:20:49 25 4
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我正在尝试实现:https://www.tensorflow.org/versions/r0.11/tutorials/wide/index.html在我的数据集上。

我基本上是尝试根据一些连续和分类特征进行二元分类(0 或 1)。

删除了 NaN,创建了新功能:

square_feet = tf.contrib.layers.real_valued_column("square_feet")
guests_included = tf.contrib.layers.real_valued_column("guests_included")
security_deposit = tf.contrib.layers.real_valued_column("security_deposit")
cleaning_fee = tf.contrib.layers.real_valued_column("cleaning_fee")
extra_people = tf.contrib.layers.real_valued_column("extra_people")

neighbourhood_group_cleansed = tf.contrib.layers.sparse_column_with_keys(column_name="neighbourhood_group_cleansed", keys=['Bronx', 'Queens', 'Staten Island', 'Brooklyn', 'Manhattan'])

host_response_time = tf.contrib.layers.sparse_column_with_keys(column_name="host_response_time", keys=['within an hour', 'within a few hours', 'within a day', 'a few days or more'])

-- 我得到了更多的功能,但我认为这传达了要点。

我复制了这些函数:

def input_fn(df):
# Creates a dictionary mapping from each continuous feature column name (k) to
# the values of that column stored in a constant Tensor.
continuous_cols = {k: tf.constant(df[k].values) for k in CONTINUOUS_COLUMNS}
# Creates a dictionary mapping from each categorical feature column name (k)
# to the values of that column stored in a tf.SparseTensor.
categorical_cols = {k: tf.SparseTensor(indices=[[i, 0] for i in range(df[k].size)], values=df[k].values, shape=[df[k].size, 1]) for k in CATEGORICAL_COLUMNS}
# Merges the two dictionaries into one.
feature_cols = dict(continuous_cols.items() + categorical_cols.items())
# Converts the label column into a constant Tensor.
label = tf.constant(df[LABEL_COLUMN].values)
# Returns the feature columns and the label.
return feature_cols, label


def train_input_fn():
return input_fn(df_train)


def eval_input_fn():
return input_fn(df_test)

稍后将被使用

model_dir = tempfile.mkdtemp()
m = tf.contrib.learn.LinearClassifier(feature_columns=FEATURE_COLUMNS, model_dir=model_dir)
m.fit(input_fn=train_input_fn, steps=200)

如果我进行一些调试,函数 input_fn() 是否会返回有效的 dict分类。但是,我收到此错误:

/lib/python2.7/site-packages/tensorflow/contrib/layers/python/layers/feature_column_ops.pyc in check_feature_columns(feature_columns)
510 seen_keys = set()
511 for f in feature_columns:
--> 512 key = f.key
513 if key in seen_keys:
514 raise ValueError('Duplicate feature column key found for column: {}. '
AttributeError: 'str' object has no attribute 'key'

feature_cols 的调试输出(仅摘录):

'square_feet': <tf.Tensor 'Const_15:0' shape=(10000,) dtype=float64>,
'guests_included': <tf.Tensor 'Const_16:0' shape=(10000,) dtype=float64>,
'security_deposit': <tf.Tensor 'Const_17:0' shape=(10000,) dtype=float64>,
'cleaning_fee': <tf.Tensor 'Const_18:0' shape=(10000,) dtype=float64>,
..

标签

<tf.Tensor 'Const_27:0' shape=(10000,) dtype=int64>

对于df[LABEL_COLUMN].values:

array([1, 1, 1, ..., 1, 1, 1])

非常感谢帮助、提示、提示。这些是我使用 Tensorflow 的第一步,我不知道如何继续或进一步排除错误。

谢谢!

--- 更新 ---

我尝试使用

import tensorflow.contrib.learn.python.learn as learn

现在在 DNN 分类器上,仅在连续列上

classifier = learn.DNNClassifier(hidden_units=[10, 20, 10], n_classes=2, feature_columns=CONTINUOUS_COLUMNS)

classifier.fit(df_train[CONTINUOUS_COLUMNS], df_train['classification'], steps=200, batch_size=32)

并得到相同的错误

/lib/python2.7/site-packages/tensorflow/contrib/layers/python/layers/feature_column_ops.pyc in check_feature_columns(feature_columns)
510 seen_keys = set()
511 for f in feature_columns:
--> 512 key = f.key
513 if key in seen_keys:
514 raise ValueError('Duplicate feature column key found for column: {}. '

AttributeError: 'str' object has no attribute 'key'

最佳答案

当你训练模型时,你会向它传递列表FEATURE_COLUMNS,我相信你有一个字符串列表。当 tensorflow 循环遍历该列表时,它尝试访问失败的字符串上的关键属性。您可能想向其传递 tensorflow 变量列表,即定义一个新列表 wide_columns:

wide_columns=[square_feet, guests_included,...]
m = tf.contrib.learn.LinearClassifier(feature_columns=wide_columns, model_dir=model_dir)
m.fit(...)

关于python - tensorflow 逻辑回归,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/40070064/

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