java - 无法转换 opennlp Parse 的结果

Question

我正在使用 opennlp 的 Parse 模型来解析一行输入，我的代码:

public void parse(String input){
InputStream modelIn = null;
try {
    modelIn = new FileInputStream("en-parser-chunking.bin");
  ParserModel model = new ParserModel(modelIn);
    opennlp.tools.parser.Parser parser = ParserFactory.create(model);
    opennlp.tools.parser.Parse topParses[] = ParserTool.parseLine(input, parser, 1);
for (opennlp.tools.parser.Parse p : topParses){
            p.show();

                         }
}catch (IOException e) {
  e.printStackTrace();
}finally {
  if (modelIn != null) {
    try {
      modelIn.close();
    }
    catch (IOException e) {
    }
  }
}
    }

如果我的输入是这是一条测试线p.show 显示 (TOP (S (NP (DT this)) (VP (VBZ is) (NP (DT a) (NN test) (NN line)))))但是 p.toString 显示 this is a test line

如何让它和 p.show 一样？

Answer 1

这对我有用...你必须使用重载显示，它会在内部更新传入的 StringBuffer 引用

public void parse(String input){
InputStream modelIn = null;
try {
    modelIn = new FileInputStream("en-parser-chunking.bin");
  ParserModel model = new ParserModel(modelIn);
    opennlp.tools.parser.Parser parser = ParserFactory.create(model);
    opennlp.tools.parser.Parse topParses[] = ParserTool.parseLine(input, parser, 1);
    for (opennlp.tools.parser.Parse p : topParses){

      StringBuilder sb = new StringBuilder(input.length() * 4);
      p.show(sb);
      //sb now contains all the tags
      System.out.println(sb);

    }
}catch (IOException e) {
  e.printStackTrace();
}finally {
  if (modelIn != null) {
    try {
      modelIn.close();
    }
    catch (IOException e) {
    }
  }
}
}