java - JSON: "Unexpected character (<) at position 0"

Question

这是获取 channel 摘要的 twitch.tv api 请求:http://api.justin.tv/api/streams/summary.json?channel=mychannel .如果我通过浏览器发布它，我会得到正确的结果。但在结果解析过程中，我以编程方式收到异常。

我使用 apache HttpClient 发送请求和接收响应。和JSON——简单解析JSON内容。

这就是我尝试根据 api 从响应中获取 JSON 的方式:

HttpClient httpClient = HttpClients.createDefault();
HttpGet getRequest = new HttpGet(new URL("http://api.justin.tv/api/streams/summary.json?channel=mychannel").toURI());
getRequest.addHeader("Accept", "application/json");
HttpResponse response = httpClient.execute(getRequest);

BufferedReader br = new BufferedReader(new InputStreamReader(response.getEntity().getContent()));
String output;
StringBuilder builder = new StringBuilder();
while((output = br.readLine()) != null) {
    builder.append(output);
}
br.close();

JSONParser parser = new JSONParser();
Object obj = parser.parse(builder.toString()); //Exception occurs here

预期结果:{"average_bitrate":0,"viewers_count":"0","streams_count":0} ，但执行上述示例会导致:Unexpected character (<) at position 0.

如何从响应中获取 JSON 正文？浏览器正确显示结果。

Answer 1

试试这个:

        URL url = new URL("http://api.justin.tv/api/stream/summary.json?channel=mychannel");
        HttpURLConnection request1 = (HttpURLConnection) url.openConnection();
        request1.setRequestMethod("GET");
        request1.connect();
        InputStream is = request1.getInputStream();
        BufferedReader bf_reader = new BufferedReader(new InputStreamReader(is));
        StringBuilder sb = new StringBuilder();
        String line = null;
        try {
            while ((line = bf_reader.readLine()) != null) {
                sb.append(line).append("\n");
            }
        } catch (IOException e) {
        } finally {
            try {
                is.close();
            } catch (IOException e) {
            }
        }
        String responseBody = sb.toString();
        JSONParser parser = new JSONParser();
        Object obj = parser.parse(responseBody);
        System.out.println(obj);