javascript - 如何根据字符串匹配拉取嵌套对象？

Question

activePath 会根据 api 调用动态变化，如何根据嵌套对象中匹配的 activePath 字符串拉取对象？

路径示例:Drug/GetRefills 在这种情况下它应该推送 data.Drug.getRefills 如果路径是 Payment/getAccount 它应该推送 data.Payment.getAccount

主要.js

const data = 
    [{
        id: 11,
        name: "Drug",
        children: [{
            id: 12,
            name: "getRefills"
        }, {
            id: 13,
            name: "getDetails"
        }]
    }, {
        id: 14,
        name: "Payment",
        children: [{
            id: 15,
            name: "getAccount"
        }, {
            id: 16,
            name: "getAccountDetails"
        }]
    }]


  function getModelData(data){
        var activePath = "Drug/GetRefills";
        var _interfaces = [];   
        $.each(data, function(id, item){
            if (activePath.toLowerCase().includes(item.name)) {
                console.log('OBJ', item);
                _interfaces.push(item);   // it should push getrefills object into interfaces   
            } 
        });

         return _interfaces;
    }

Answer 1

可以使用递归来查找对象(类似于DFS):

const data = [{
  id: 11,
  name: "Drug",
  children: [{
    id: 12,
    name: "getRefills"
  }, {
    id: 13,
    name: "getDetails"
  }]
}, {
  id: 14,
  name: "Payment",
  children: [{
    id: 15,
    name: "getAccount"
  }, {
    id: 16,
    name: "getAccountDetails"
  }]
}];


function getModelData(path) {
  function find(arr, [key, ...rest]) {
    const obj = arr.find(o => o.name === key);
    if (!obj) return null;
    return rest.length ? find(obj.children || [], rest) : obj;
  }

  return find(data, path.split('/'));
  // Instead of returning, add the found object to _interfaces
}

console.log(getModelData('Drug/getRefills'));
console.log(getModelData('Drug/getRefillsss'));
console.log(getModelData('Payment/getAccountDetails'));