java - Spring Security JAAS 认证授权问题

Question

在 Spring Security 中，我使用 DefaultJaasAuthenticationProvider 配置使用 linux 用户名/密码进行登录身份验证。JpamLoginModule 用于身份验证。我成功通过了身份验证，但我在授权方面遇到了问题(ROLE_USER，ROLE_ADMIN)，我收到 HTTP 状态 403 - 访问被拒绝错误。

以下是我在 spring-security.xml 中使用的配置

<security:authentication-manager>
    <security:authentication-provider ref="jaasAuthProvider" />
</security:authentication-manager>

<bean id="jaasAuthProvider"  class="org.springframework.security.authentication.jaas.DefaultJaasAuthenticationProvider">
    <property name="configuration">
        <bean class="org.springframework.security.authentication.jaas.memory.InMemoryConfiguration">
            <constructor-arg>
                <map>
                    <entry key="SPRINGSECURITY">
                        <array>
                            <bean class="javax.security.auth.login.AppConfigurationEntry">
                                <constructor-arg value="net.sf.jpam.jaas.JpamLoginModule" />
                                <constructor-arg>
                                    <util:constant  static-field="javax.security.auth.login.AppConfigurationEntry$LoginModuleControlFlag.REQUIRED" />
                                </constructor-arg>
                                <constructor-arg>
                                    <map></map>
                                </constructor-arg>
                            </bean>
                        </array>
                    </entry>
                </map>
            </constructor-arg>
        </bean>
    </property>
    <property name="authorityGranters">
        <list>
            <bean class="it.webapps.pam.RoleGranter" />
        </list>
    </property>
</bean> 
    <bean id="userDetailsService" class="it.webapps.pam.UserDetailsServiceImpl">  
</bean> 

RoleGranter.java代码

public class RoleGranter implements AuthorityGranter {

public RoleGranter() {
    System.out.print("=== Creating My Authority Granter ===");
 }

@Override
public Set<String> grant(Principal principal) {

        return Collections.singleton("ROLE_ADMIN");
}

建议会很有帮助

Answer 1

基于:http://jpam.sourceforge.net/xref/net/sf/jpam/jaas/JpamLoginModule.html和 https://github.com/spring-projects/spring-security/blob/master/core/src/main/java/org/springframework/security/authentication/jaas/AbstractJaasAuthenticationProvider.java

看起来您需要扩展 JpamLoginModule 来更改提交的行为。在您的扩展 JpamLoginModule 中，需要将主体分配给主题。然后 AbstractJaasAuthenticationProvider (DefaultJaasAuthenticationProvider) 将循环遍历这些委托(delegate)人并将它们发送给您的 authorityGranters (RoleGranter)。

<authentication-manager>
    <authentication-provider ref="jaasAuthProvider" />
</authentication-manager>

<beans:bean id="userService" class="blah.UserDetailsServiceImpl" />  

<beans:bean id="jaasAuthProvider"  class="org.springframework.security.authentication.jaas.DefaultJaasAuthenticationProvider">
    <beans:property name="configuration">
        <beans:bean class="org.springframework.security.authentication.jaas.memory.InMemoryConfiguration">
            <beans:constructor-arg>
                <beans:map>
                    <beans:entry key="SPRINGSECURITY">
                        <beans:array>
                            <beans:bean class="javax.security.auth.login.AppConfigurationEntry">
                                <beans:constructor-arg value="blah.RoleGrantingJpamLoginModule" />
                                <beans:constructor-arg>
                                    <util:constant  static-field="javax.security.auth.login.AppConfigurationEntry$LoginModuleControlFlag.REQUIRED" />
                                </beans:constructor-arg>
                                <beans:constructor-arg>
                                    <beans:map></beans:map>
                                </beans:constructor-arg>
                            </beans:bean>
                        </beans:array>
                    </beans:entry>
                </beans:map>
            </beans:constructor-arg>
        </beans:bean>
    </beans:property>
    <beans:property name="authorityGranters">
        <beans:list>
            <beans:bean class="blah.RoleGranter" />
        </beans:list>
    </beans:property>
</beans:bean> 

package blah;

import javax.security.auth.Subject;
import javax.security.auth.login.LoginException;

import net.sf.jpam.jaas.JpamLoginModule;

import org.springframework.security.authentication.UsernamePasswordAuthenticationToken;

public class RoleGrantingJpamLoginModule extends JpamLoginModule {
    private Subject subject;

    @Override
    public void initialize(javax.security.auth.Subject subject, javax.security.auth.callback.CallbackHandler callbackHandler, java.util.Map sharedState, java.util.Map options) {
        super.initialize(subject, callbackHandler, sharedState, options);
        this.subject = subject;
    }

    @Override
    public boolean commit() throws LoginException {
        UsernamePasswordAuthenticationToken token = new UsernamePasswordAuthenticationToken(null, null);
        subject.getPrincipals().add(token);
        return super.commit();
    }
}


package blah;

import static java.util.Arrays.asList;

import org.springframework.security.core.authority.SimpleGrantedAuthority;
import org.springframework.security.core.userdetails.User;
import org.springframework.security.core.userdetails.UserDetails;
import org.springframework.security.core.userdetails.UserDetailsService;
import org.springframework.security.core.userdetails.UsernameNotFoundException;

public class UserDetailsServiceImpl implements UserDetailsService {

    @Override
    public UserDetails loadUserByUsername(String username) throws UsernameNotFoundException {
        return new User(username, "password", asList(new SimpleGrantedAuthority("ROLE_ADMIN")));
    }

}