java - 随机井字游戏图像翻转

Question

我创建了一个基本的 Tic-Tac-Toe 类，它显示 9 个按钮，上面显示随机图像(每次运行时 - 不同的序列)。主要方法在另一个测试类中，它只是一个框架创建者。除此之外，我想添加一些事件处理。我已将“ActionListener”添加到按钮并想在“actionPerformed”方法中添加一些逻辑。每次我点击任何按钮时，它应该按 X -> O -> Blank -> X 的顺序连续更改图像。我不确定哪种逻辑适合这里以按上述顺序翻转图像(例如 for-loop，switch ETC。)。代码如下:

 import javax.swing.*;
 import java.awt.*;
 import java.awt.event.*;

 public class TicTacToe extends JFrame {

  public JButton[][] labels = new JButton[3][3];
  public ImageIcon[] icons = new ImageIcon[3];
  public int r, c;

  public TicTacToe() {
    // TODO Auto-generated constructor stub

    setLayout(new GridLayout(3, 3));


    for (r = 0; r < labels.length; r++) {
     for (c = 0; c < labels.length; c++) {
      int random = (int)(Math.random() * 3 + 0);
      System.out.println(random);
      JButton s = new JButton(this.icons[random]);
      this.add(s);
      this.labels[r][c] = s;

      if (random == 0) {
       System.out.println("Cross Image Icon");
       labels[r][c].setIcon(new ImageIcon("C:\\Users\\yogesh\\workspace\\hw3pandarey\\src\\hw3pandarey\\cross_symbol.gif"));
       add(labels[r][c]);
       validate();
      } else if (random == 1) {
       System.out.println("Not Image Icon");
       labels[r][c].setIcon(new ImageIcon("C:\\Users\\yogesh\\workspace\\hw3pandarey\\src\\hw3pandarey\\zero_symbol.gif"));
       add(labels[r][c]);
       validate();
      } else if (random == 2) {
       System.out.println("Keep it blank");
       labels[r][c].setIcon(new ImageIcon());
       add(labels[r][c]);
       validate();
      }

      labels[r][c].addActionListener(new ButtonListener());

     }
    }


   } // end of TicTacToe constructor 

  public class ButtonListener implements ActionListener {

   public void actionPerformed(ActionEvent e) {

    } // end of actionPerformed method 

  } // end of ButtonListener class                  


 } // end of TicTacToe class

 import javax.swing.*;

 public class TicTacToeTest {

  public static void main(String[] args) {
    TicTacToe frame = new TicTacToe();
    frame.setTitle("Let's play a random tic-tac-toe game !!!!!");
    frame.setSize(400, 400);
    frame.setLocationRelativeTo(null);
    frame.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
    frame.setVisible(true);

   } //end of main method       
 } // end of test class

Answer 1

您可以像这样使用 setText 方法在 JButton 上放置 X 或 O。您只需要添加一个变量即可知道它是 X 转弯还是 O 转弯。希望这有帮助

public class ButtonListener implements ActionListener 
     {

        public void actionPerformed(ActionEvent e) 
        {
            Object src = e.getSource();
                for(int i = 0; i < 3; i++) {
                for (int j = 0; j < 3; j++) {
                    if(src==labels[i][j]&&labels[i][j].getText()==""){
                        //if X turn 
                        labels[i][j].setText("X");

                    }
                    //if O turn
                    //labels[i][j].setText("O");
                }
            }

                }// end of actionPerformed method 

     } // end of ButtonListener class