java - 单击返回时在 SearchView 中重置搜索

Question

我添加了搜索菜单项来过滤我的列表。过滤和重置过滤器一切正常。但是当用户单击后退按钮时，我找不到重置过滤器的方法。实际上，当用户在搜索字段中添加一些文本时，第一次后退单击将隐藏键盘，第二次单击将折叠搜索字段并删除我的搜索文本......但列表仍然被过滤。我应该怎么做才能重置列表？

@Override
public boolean onCreateOptionsMenu(Menu menu) {

    MenuInflater inflater = getMenuInflater();
    inflater.inflate(R.menu.search_menu, menu);

    searchMenuItem = menu.findItem(R.id.action_search);
    SearchView mSearchView = (SearchView) MenuItemCompat.getActionView(searchMenuItem);

    if (mSearchView != null) {
        mSearchView.setIconifiedByDefault(true);
        mSearchView.setOnQueryTextListener(this);
    }
    return super.onCreateOptionsMenu(menu);
}

@Override
public boolean onQueryTextChange(String s) {
    refreshSearch(s);
    return false;
}

private void refreshSearch(String s) {
    FragmentManager fm = getSupportFragmentManager();
    MyListFragment listFragment = (MyListFragment)fm.getFragments().get(0);
    MyArrayAdapter arrayAdapter = (MyArrayAdapter)listFragment.getListAdapter();
    arrayAdapter.getFilter().filter(s);
}

通过添加一些额外的代码来编辑我的问题，这可能有助于了解原因

@Override
public boolean onQueryTextSubmit(String s) {
    hideKeyboard();
    return false;
}
@Override
public boolean onQueryTextChange(String s) {
    refreshSearch(s);
    return false;
}
@Override
public boolean onOptionsItemSelected(MenuItem item) {
    // Handle presses on the action bar items
    switch (item.getItemId()) {
        case R.id.action_search:
            return true;
        default:
            return false; //return super.onOptionsItemSelected(item);
    }
}

Answer 1

我通过这样做解决了问题:

searchMenuItem.setOnActionExpandListener(new MenuItem.OnActionExpandListener() {

        @Override
        public boolean onMenuItemActionExpand(MenuItem item) {
            return true;
        }

        @Override
        public boolean onMenuItemActionCollapse(MenuItem item) {
            refreshSearch("");
            return true;
        }
    });