java - 使用扫描仪评估字符串中的单词

Question

我正在尝试编写一种方法，该方法从“words”参数返回至少具有“min”但不超过“max c”个字符的单词数。

public static int countWords(String words, int min, int max)
{
    Scanner s = new Scanner (words);
    int counter = 0;

 while  (s.hasNext())
    {
    String word = s.next();
    int wordLength = word.length();
    if (wordLength>min && wordLength<max)
    {
        counter= counter + 1;
        s.close();
        }
    }
    return counter;
}

Answer 1

只是一个小改动。您正在 while 循环中关闭扫描仪，将其移出循环，它就可以工作了。

public static int countWords(String words, int min, int max) {
        Scanner s = new Scanner(words);
        int counter = 0;
        while (s.hasNext()) {
            String word = s.next();
            int wordLength = word.length();
            if (wordLength > min && wordLength < max) {
                counter = counter + 1;
            }
        }
        s.close();
        return counter;
    }

我还建议您更改 if 条件，使其包含最小值和最大值。如果(wordLength >= min && wordLength =< max){例如 countWords("count words in this line 1 22 333 4444 55555",3,4) 不会返回任何字符串的结果。