javascript - 将 JS 代码放入 PHP while 循环中

Question

我有一些用于显示图形数据的 JS 代码:

series: [{
                name: 'Year 1800',
                data: [107, 31, 635, 203, 2]
            }, {
                name: 'Year 1900',
                data: [133, 156, 947, 408, 6]
            }, {
                name: 'Year 2008',
                data: [973, 914, 4054, 732, 34]
            }]

我需要获取数据以在 PHP 的 while 循环中显示。我试过这个:

<?php
                $sql="SELECT *, COUNT(category) AS my_groupcount from tickets where deleted = '' and DAY(datetime) = '".$day."' and MONTH(datetime) = '".$month."' and YEAR(datetime) = '".$year."' group by category order by datetime ASC ";
                $rs=mysql_query($sql,$conn);
                while($result=mysql_fetch_array($rs))
                {
                    echo "name: 'Cat ".$result["category"]."',";
                    echo "data: [".$result["my_groupcount"]."]";
                    echo "}, {";
                }
                ?>

我需要在门票表中对类别列进行分组并显示每个类别的图表，但它不起作用 - 我认为这是因为在 while 循环中它以 }, { 结尾，但我需要它以 }]

结尾

我怎样才能解决这个问题 - 由于用户能够添加/删除类别，门票表中类别项目的数量一直在变化。

Answer 1

为什么不这样做:

<?php
    $sql = "[.. SQL Statement ..]";
    $rs = mysql_query($sql, $conn);
    $json = array();

    while($result = mysql_fetch_array($rs)) {
        $json[] = array( 
            'name' => 'Cat '. $result['category'],

            // This does assume that my_groupcount is an array with numbers
            // i.e. array(1, 34, 54, 345)
            // If not, you'll have to make it an array by doing:
            // explode(', ', $result['my_groupcount'])
            // This however does assume that the numbers are in 
            // the "12, 23" format
            'data' => $result['my_groupcount'],
        );
    }             

    echo json_encode($json);