java - 我有一个 double 组，我需要得到一个中位数，但它一直给我一个 int 转换错误

Question

如果没有这种方法，我不知道如何获得中位数，但它一直说转换错误。我知道这是因为我将 numbers.length 除以 2，但我不知道如何让程序理解它是一个 double 。它在我不断收到错误的底部。这是我的最后一个 if else 语句。我到处搜索，如果这是重复的，我很抱歉，但我找不到。我也无法转换为整数，因为我的数组由 double 组成。在此先感谢帮助我的人。

import static java.lang.Math.*;
import java.util.Scanner;
import java.util.Arrays;
public class ComputingArrays
{
    public static void main(String[] args) {
        Scanner in = new Scanner(System.in);

        double [] numbers = {33.5, 67.5, 67.5, 88.0, 46.0, 94.5, 77.5, 83.0, 95.0, 80.5}; // declare, allocate memory, and store values

        double n = numbers.length; // get length of array
        Arrays.sort(numbers);
        System.out.println("The Array of Numbers are :");
        double sum = 0; //initiate and declare sum
        for (int i = 0; i < n; i++) {  //loop through n numbers
            System.out.println(numbers[i]);
            sum = sum + numbers[i];
        }      
        final double average = sum / n;
        System.out.println("The Sum of the Array is " + sum);
        System.out.println("The Average of the Array is " + average);

        double var1 = 0;
        double var2 = 0;
        double varSum = 0;
        for (int i = 0; i < n; i++) { 
            var1 = numbers[i] - average;            
            var2 = var1 * var1; // to square
            varSum = varSum + var2; // to get sum of all squared differences
        }
        double variance = varSum / n;
        System.out.printf("The Variance of the Array is  %.2f %n", variance); //%.2f rounds two decimal places 

        System.out.printf("The Standard Deviation is %.3f %n", Math.sqrt(variance));

        double middle = numbers.length / 2.0;
        double median = 0.0;
        if (numbers.length % 2 == 1){
            median = numbers[middle];
            System.out.println("The median is " + median);
        }
        else {
            median = (numbers[middle-1] + numbers[middle]) / 2;
            System.out.println("The median is " + median);
        }
    }
}

Answer 1

当索引数组时，它需要 int 而不是 double，因为像 5.5 这样的值不是有效索引。

有效

int middle = numbers.length / 2;
System.out.println(numbers[middle]);

无效

double middle = numbers.length / 2.0;
System.out.println(numbers[middle]);