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machine-learning - 值错误 : Input 0 is incompatible with layer conv_1: expected ndim=3, 发现 ndim=4

转载 作者:行者123 更新时间:2023-11-30 08:28:08 25 4
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我正在尝试制作一个变分自动编码器来学习编码 DNA 序列,但遇到了意外错误。

我的数据是一个由 one-hot 数组组成的数组。

我遇到的问题是值错误。它告诉我,我有一个四维输入,而我的输入显然是三维的(100, 4008, 4)。

事实上,当我打印出 seq 层时,它说它的形状是 (?, 100, 4008, 4)。

当我取出一个维度时,它会给出一个二维错误。

任何帮助将不胜感激!

代码是:

from keras.layers import Input 
from keras.layers.convolutional import Conv1D
from keras.layers.core import Dense, Activation, Flatten, RepeatVector, Lambda
from keras import backend as K
from keras.layers.wrappers import TimeDistributed
from keras.layers.recurrent import GRU
from keras.models import Model
from keras import objectives

from one_hot import dna_sequence_to_one_hot

from random import shuffle
import numpy as np

# take FASTA file and convert into array of vectors
seqs = [line.rstrip() for line in open("/home/ubuntu/sequences.fa", "r").readlines() if line[0] != ">"]
seqs = [dna_sequence_to_one_hot(s) for s in seqs]
seqs = np.array(seqs)

# first random thousand are training, next thousand are validation
test_data = seqs[:1000]
validation_data = seqs[1000:2000]

latent_rep_size = 292
batch_size = 100
epsilon_std = 0.01
max_length = len(seqs[0])
charset_length = 4
epochs = 100

def sampling(args):
z_mean_, z_log_var_ = args
# batch_size = K.shape(z_mean_)[0]
epsilon = K.random_normal_variable((batch_size, latent_rep_size), 0., epsilon_std)
return z_mean_ + K.exp(z_log_var_ / 2) * epsilon

# loss function
def vae_loss(x, x_decoded_mean):
x = K.flatten(x)
x_decoded_mean = K.flatten(x_decoded_mean)
xent_loss = max_length * objectives.categorical_crossentropy(x, x_decoded_mean)
kl_loss = - 0.5 * K.mean(1 + z_log_var - K.square(z_mean) - K.exp(z_log_var), axis = -1)
return xent_loss + kl_loss

# Encoder
seq = Input(shape=(100, 4008, 4), name='one_hot_sequence')
e = Conv1D(9, 9, activation = 'relu', name='conv_1')(seq)
e = Conv1D(9, 9, activation = 'relu', name='conv_2')(e)
e = Conv1D(9, 9, activation = 'relu', name='conv_3')(e)
e = Conv1D(10, 11, activation = 'relu', name='conv_4')(e)
e = Flatten(name='flatten_1')(e)
e = Dense(435, activation = 'relu', name='dense_1')(e)
z_mean = Dense(latent_rep_size, name='z_mean', activation = 'linear')(e)
z_log_var = Dense(latent_rep_size, name='z_log_var', activation = 'linear')(e)
z = Lambda(sampling, output_shape=(latent_rep_size,), name='lambda')([z_mean, z_log_var])

encoder = Model(seq, z)

# Decoder
d = Dense(latent_rep_size, name='latent_input', activation = 'relu')(z)
d = RepeatVector(max_length, name='repeat_vector')(d)
d = GRU(501, return_sequences = True, name='gru_1')(d)
d = GRU(501, return_sequences = True, name='gru_2')(d)
d = GRU(501, return_sequences = True, name='gru_3')(d)
d = TimeDistributed(Dense(charset_length, activation='softmax'), name='decoded_mean')(d)



# create the model, compile it, and fit it
vae = Model(seq, d)
vae.compile(optimizer='Adam', loss=vae_loss, metrics=['accuracy'])
vae.fit(x=test_data, y=test_data, epochs=epochs, batch_size=batch_size, validation_data=validation_data)

最佳答案

在文档中提到我们需要以特定格式提及输入,即(None,NumberOfFeatureVectors)。在您的情况下,它将是 (None,4)

https://keras.io/layers/convolutional/

When using this layer as the first layer in a model, provide an input_shape argument (tuple of integers or None, e.g. (10, 128) for sequences of 10 vectors of 128-dimensional vectors, or (None, 128) for variable-length sequences of 128-dimensional vectors.

关于machine-learning - 值错误 : Input 0 is incompatible with layer conv_1: expected ndim=3, 发现 ndim=4,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/44194767/

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