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Java 多播发送方 + 接收方

转载 作者:行者123 更新时间:2023-11-30 08:27:56 25 4
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我的问题很容易解释。我有一个多播发送方和一个多播接收方。我试图发送一个 8MB 的大文件。它应该分成 1024 字节包 + 4 字节 header 。发送正常,但接收方有时会在 2000 或 3000 取消接收位置 5000。我不知道为什么它没有收到所有元素。

发件人:

import java.io.File;
import java.io.FileInputStream;
import java.io.IOException;
import java.net.DatagramPacket;
import java.net.InetAddress;
import java.net.InetSocketAddress;
import java.net.MulticastSocket;

public class Sender extends Thread{

protected static MulticastSocket socket = null;
public int QuoteCount = 0;
public int Time_Interval = 6000;
public static FileInputStream in;
final static int split_size = 1028 ;

public static void main(String[] args) throws IOException{
// args 0 => path
// args1=> ip multicast
// args2 => networkinterface ip
// args3 => port
// args4 => ttl
//socket = new MulticastSocket(444);
InetAddress ip_address_group = InetAddress.getByName(args[1]);
System.out.println("Wait 4 clients to connect...");
File file=new File(args[0]);

InetSocketAddress address = new InetSocketAddress(args[1],Integer.parseInt(args[3]));
MulticastSocket socket = new MulticastSocket(new InetSocketAddress(args[2], Integer.parseInt(args[3])));
socket.connect(address);
socket.setTimeToLive(Integer.parseInt(args[4]));

MD5 md5 = new MD5();
try {
System.out.println("MD5 vom File: "+md5.getFileMD5(args[0]));
} catch (Exception e1) {
// TODO Auto-generated catch block
e1.printStackTrace();
}

// Filesize package
int filesize = (int)file.length();

double anzpak=(filesize/1028); // anzahl pakete
double diagrammgrenze=(80/anzpak); // wieviele stricherl setzt ein paket
double strikecount=0;
System.out.println("DIAGR: "+diagrammgrenze +" Anzpak: "+anzpak);

byte[] firstpack=new byte[4];
int2bytearr(filesize,firstpack);
DatagramPacket firsttosend=new DatagramPacket(firstpack,firstpack.length,ip_address_group, Integer.parseInt(args[3]));
socket.send(firsttosend);

// Rest of packages
in = new FileInputStream(file);

byte[] data = new byte[split_size];
int numbytes = 0;
int seqnr = 0;
int sentbytes=0;

try {
while((numbytes = in.read(data)) != -1){
// Generate 4 byte long seqnr:
seqnr++;
strikecount+=diagrammgrenze;
if(strikecount>=1){
for(int i=0;i<(int)strikecount;i++){
System.out.print("|");
strikecount--;
}
}

byte[] dataseq = new byte[4];
int2bytearr(seqnr,dataseq);
sentbytes+=numbytes;

// DATA PLUS SEQNR Generation
byte[] seqplusdata = new byte[dataseq.length + data.length];
System.arraycopy(dataseq, 0, seqplusdata, 0, dataseq.length);
System.arraycopy(data, 0, seqplusdata, dataseq.length, data.length);

// Data Plus Seqnr Sending
DatagramPacket tosend=new DatagramPacket(seqplusdata,seqplusdata.length);
socket.send(tosend);
}

} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}

System.out.println("\nTosend filesize: "+filesize);
System.out.println("Sent bytes: "+sentbytes);
//in.close();
socket.close();
}

public static void int2bytearr(int number,byte[] data){
for (int i = 0; i < 4; ++i) {
int shift = i << 3; // i * 8
data[3-i] = (byte)((number & (0xff << shift)) >>> shift);
}
}

}

接收者:

import java.io.IOException;
import java.net.MulticastSocket;
import java.net.DatagramPacket;
import java.net.InetAddress;

public class Empfaenger extends Thread{

public static void main(String[] args) throws IOException{
Empfaenger empfaenger = new Empfaenger();
empfaenger.start();
}

@SuppressWarnings("resource")
public void run(){
try{

//Create socket
MulticastSocket socket = new MulticastSocket(12345);

//Connect to server (must be multicast)
InetAddress IP_Adress = InetAddress.getByName("228.5.6.7");
socket.joinGroup(IP_Adress);

DatagramPacket packet;
int pcount=0;

// firstpack for getting filesize package
byte[] firstpack = new byte[4];
DatagramPacket firstpacket=new DatagramPacket(firstpack,firstpack.length);
socket.receive(firstpacket);
int filesize=makeintfrombyte(firstpack);
System.out.println("Empfaenger filesize: " + filesize);

double anzpak=(filesize/1028); // anzahl pakete
double diagrammgrenze=(80/anzpak); // wieviele stricherl setzt ein paket
double strikecount=0;

for(int i=0;i<anzpak;i++){
System.out.println(pcount + "< "+anzpak);

strikecount+=diagrammgrenze;
if(strikecount>=1){
while(strikecount>=1){
System.out.print("|");
strikecount--;
}
}

byte[] buf = new byte[1028];
packet = new DatagramPacket(buf, buf.length);
socket.receive(packet);
pcount++;
//System.out.println("SeqNr. in Bytes: "+buf[0]+"|"+buf[1]+"|" +buf[2]+"|" +buf[3]+"|" + pcount);
}
//socket.leaveGroup(IP_Adress);
//socket.close();

}catch ( IOException X) {System.out.println(X);}
}

public int makeintfrombyte(byte[] b){
return b[0] << 24 | (b[1] & 0xff) << 16 | (b[2] & 0xff) << 8 | (b[3] & 0xff);
}

}

这里是接收方和一个发送方的示例输出] http://i.stack.imgur.com/UblCa.jpg

编辑:如果我们让发件人 sleep (长)1.0 它有效,但这不是让发件人 sleep 的意思:(

最佳答案

数据报不保证交付,因此它不是传输文件的理想协议(protocol)。您可能需要考虑使用可靠的多播协议(protocol)。

最后,如果您的发送速率高于接收速率,您最终会丢弃数据包。事实上,即使速率非常相似,接收端(例如调度程序、垃圾收集器等)的任何临时减速都足以开始下降。通过调用 setReceiveBufferSize 增加底层网络缓冲区大小会给你一些利润并大大改善行为。默认值通常为 128K,至少在 UX 系统上是这样;尝试将其设置为几 MB。

关于Java 多播发送方 + 接收方,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/20525224/

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