java - includeProperties 不起作用？

Question

struts.xml:

<action name="findTspNameIdMap"
            class="cdot.oss.cmsat.gma.struts.ConfigureTspThresholdAction" method="findTspNameIdMap">

            <result name="success" type="json">
                <param name="includeProperties">result,tspNameIdMap.*</param>   
            </result> 

            <result name="error">pages/Error.jsp</result>

        </action>

Action 类:

public class ConfigureTspThresholdAction extends ActionSupport implements SessionAware, ModelDriven<GmaThresholdParameter>{


    private Map<String,Object> session;
    private String operatorId;

    private Map<String,String> tspNameIdMap;
    private String result = "success";

    //private List<String> thresholdParameters;
    GmaThresholdParameter gmaThresholdParameters = new GmaThresholdParameter();

我对操作执行 AJAX 调用，当我在 Firebug 中检查 JSON 响应时，它是:{} .但是，如果我这样做 <param name="root">tspNameIdMap</param>它有效但无效 includeProperties .

早些时候它可以工作，但我做了一些代码更改(与上面的代码部分无关)并且它停止工作了。代码更改包括实现 ModelDriven对于 POJO。

为什么不工作？有帮助吗？

Answer 1

已解决:

struts.xml:

   <result name="success" type="json">
        <param name="root">action</param>         
        <param name="includeProperties">result,tspNameIdMap.*</param>   
    </result-type>

我添加了 <param name="root">action</param>到我的代码，它解决了问题。

从我解决的地方引用这个链接:http://blog.mattsch.com/2011/04/14/things-discovered-in-struts-2/

Since Struts 2.2.3 the root object is always considered to be the model if the action is model >driven. This means that when creating the JSON request only the model will get serialized. In >some cases one might use model driven for receiving requests and send something else in the >response. Then the root object has to be changed. This can be done by setting the root >parameter as shown above.