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javascript - 从 Javascript 数组创建嵌套的 Json 结构

转载 作者:行者123 更新时间:2023-11-30 08:22:24 26 4
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我正在寻找一个有效的嵌套 Json 文件,从一个数组,具有唯一的键值。目前,我只能显示没有任何嵌套结构的 json。

我想向控制台显示以下结构:

{
"Key" : "data1",
"header" : {
"title" : "data2",
"tag1" : "data3",
"tag2" : "data4"
},
"body" : {
"text" : "data5"
},
"updates" : {
"title" : "data6",
"text" : "data7"
},
"footer" : {
"title" : "data8",
"row1" :{
"col1" : {
"title" : "data9",
"text" : "data10"
},
"col2" : {
"title" : "data11",
"text" : "data12"
},
"col3" : {
"title" : "data13",
"text" : "data14"
}
},
"row2" :{
"col1" : {
"title" : "data15",
"text" : "data16"
},
"col2" : {
"title" : "data17",
"text" : "data18"
},
"col3" : {
"title" : "data19",
"text" : "data20"
}
},
"row3" :{
"col1" : {
"title" : "data22",
"text" : "data23"
},
"col2" : {
"title" : "data24",
"titlebis" : "data25",
"text" : "data26"
},
"col3" : {
"title" : "data27",
"text" : "data28"
}
},
"row4" :{
"col1" : {
"title" : "data29"
},
"website" : "data30",
"website-link" : "data31",
"email" : "data38",
"privacy" : "data32",
"privacy-link" : "data33",
"adr" : "data34",
"adr2" : "data35"
}
},
"other" : {
"short" : {
"des" : "data36"
},
"promovideo" : "data37"
}
}

这是我已经完成的:

  var data = [["Key", "data1"],
["header.title", "data2"],
["header.tag1", "data3"],
["header.tag2", "data4"],
["body.text", "data5"],
["updates.title", "data6"],
["updates.text", "data7"],
["footer.title", "data8"],
["footer.row1.col1.title", "data9"],
["footer.row1.col1.text", "data10"],
["footer.row1.col2.title", "data11"],
["footer.row1.col2.text", "data12"],
["footer.row1.col3.title", "data13"],
["footer.row1.col3.text", "data14"],
["footer.row2.col1.title", "data15"],
["footer.row2.col1.text", "data16"],
["footer.row2.col2.title", "data17"],
["footer.row2.col2.text2", "data18"],
["footer.row2.col3.title", "data19"],
["footer.row2.col3.text", "data20"],
["footer.row3.col1.title", "data22"],
["footer.row3.col1.text", "data23"],
["footer.row3.col2.title", "data24"],
["footer.row3.col2.title", "data25"],
["footer.row3.col2.text", "data26"],
["footer.row3.col3.title", "data27"],
["footer.row3.col3.text", "data28"],
["footer.row4.col1.title", "data29"],
["footer.row4.website", "data30"],
["footer.row4.website-link", "data31"],
["footer.row4.email", "data31"],
["footer.row4.privacy", "data32"],
["footer.row4.privacy-link", "data33"],
["footer.row4.adr", "data34"],
["footer.row4.adr2", "data35"],
["other.short.des", "data36"],
["other.promovideo", "data37"],
];
// console.log(data);

data.sort(alphabetical); // Sort alphabetically our 2D array

CreateAndDisplayJson(data);

// Create a JSON file from Keys Trad Data
function CreateAndDisplayJson(GetKeysTraductionArrayData) {
var lenght = GetKeysTraductionArrayData.length;
var output = "{\n";

for (var i = 0; i < GetKeysTraductionArrayData.length; i++) {
var key = GetKeysTraductionArrayData[i][0];
var trad = GetKeysTraductionArrayData[i][1];

var nameSplit = key.split("."); // Check how many times we need to indent json from Key

if(nameSplit.length>1) { // The Key needs to be indented

var closeBraket = "";
var spacing = ""; // Json indentation
var saveSpacingTab = []; // Closing indentation

for (j=0; j <nameSplit.length; j++){ // We add the key + indentation
output += spacing+"\""+nameSplit[j]+"\" : { \n";
if (j==0 && i != GetKeysTraductionArrayData.length-1) {
closeBraket = spacing+"}, \n";
} else {
closeBraket = spacing+"} \n";
}
spacing +=" ";
saveSpacingTab[j] = closeBraket;
closingText = "";

if (j==nameSplit.length-1) { // last indentation of the Key
saveSpacingTab.reverse();
for ( k=0; k < saveSpacingTab.length ; k++) { // We create the Bracket indentation
closingText += saveSpacingTab[k];
}
output += spacing+"\""+nameSplit[j]+"\" : " + "\""+trad +"\"\n" + closingText; // last Row
}
}
} else {
output += "\""+key+"\" : " + "\""+trad +"\", \n";
}
}
// output += "}" + outputCommented;
output += "}";
console.log(output);
return output;
}

// Sort alphabetically our 2D array
function alphabetical(a, b) {
var A = a[0];
var B = b[0].toLowerCase();

A = A.toLowerCase();
B = B.toLowerCase();

if (A < B) return -1;
if (A > B) return 1;
return 0;
}

最佳答案

您可以使用 forEach 循环并在 split 中每个键,然后使用 reduce 为每个键构建嵌套结构。

var data = [["Key","data1"],["header.title","data2"],["header.tag1","data3"],["header.tag2","data4"],["body.text","data5"],["updates.title","data6"],["updates.text","data7"],["footer.title","data8"],["footer.row1.col1.title","data9"],["footer.row1.col1.text","data10"],["footer.row1.col2.title","data11"],["footer.row1.col2.text","data12"],["footer.row1.col3.title","data13"],["footer.row1.col3.text","data14"],["footer.row2.col1.title","data15"],["footer.row2.col1.text","data16"],["footer.row2.col2.title","data17"],["footer.row2.col2.text2","data18"],["footer.row2.col3.title","data19"],["footer.row2.col3.text","data20"],["footer.row3.col1.title","data22"],["footer.row3.col1.text","data23"],["footer.row3.col2.title","data24"],["footer.row3.col2.title","data25"],["footer.row3.col2.text","data26"],["footer.row3.col3.title","data27"],["footer.row3.col3.text","data28"],["footer.row4.col1.title","data29"],["footer.row4.website","data30"],["footer.row4.website-link","data31"],["footer.row4.email","data31"],["footer.row4.privacy","data32"],["footer.row4.privacy-link","data33"],["footer.row4.adr","data34"],["footer.row4.adr2","data35"],["other.short.des","data36"],["other.promovideo","data37"]]

let result = {}
data.forEach(([key, value]) => {
key.split('.').reduce((r, k, i, arr) => {
return r[k] || (r[k] = arr[i + 1] ? {} : value)
}, result)
})

console.log(result)

关于javascript - 从 Javascript 数组创建嵌套的 Json 结构,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/51329207/

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