javascript - 避免在过滤器循环中使用多个 indexOf

Question

我需要检查一个字符串是否有几个值的任何 indexOf。我想避免这样的事情:

  let filter = tasks.filter(
    x =>
      x.eventData.workflow_name === brand &&
      (x.eventData.task_queue_name.indexOf('Value1') == -1 &&
        x.eventData.task_queue_name.indexOf('_Value2') == -1 &&
        x.eventData.task_queue_name.indexOf('Value3') == -1 &&
        x.eventData.task_queue_name.indexOf('BANG_Value4') == -1)
  )

我试图创建一个类似 const VALUES_TO_SKIP = ['Value1', ...] 的数组，并在一行中写入 indexOf 条件。

有没有可能避免一堆value.indexOf(...)？

Answer 1

您可以使用 Array.some 或 Array.every，例如:

// The values to Test out
const arrayOfValue = [
  'Value1',
  '_Value2',
  'Value3',
  'BANG_Value4',
];

// Your data to filters
const tasks = [{
  eventData: {
    workflow_name: 'brand',
    task_queue_name: 'BANG_Value3 and Value2 and Value3',
  },
}, {
  eventData: {
    workflow_name: 'brand',
    task_queue_name: 'Dogs loves cat',
  },
}, {
  eventData: {
    workflow_name: 'brand',
    task_queue_name: 'Dogs loves BANG_Value4',
  },
}];

const brand = 'brand';

const filtered = tasks.filter(x =>
  x.eventData.workflow_name === brand &&
  !arrayOfValue.some(y => x.eventData.task_queue_name.includes(y))
);

console.log(filtered);