gpt4 book ai didi

java - 从后缀表达式创建二叉树

转载 作者:行者123 更新时间:2023-11-30 08:19:16 24 4
gpt4 key购买 nike

假设我有以下后缀表达式:5372-*-

我想从这个表达式创建一个二叉树。我的算法是:如果我的字符是数字,则将其放入堆栈中,如果它是运算符,则从堆栈中弹出两个元素,并使它们成为运算符的子元素。然后将运算符压入堆栈。这看起来像是有效的,但我无法连接我创建的小树。

我当前的代码是:

public void myInsert(char ch, Stack s) {
if (Character.isDigit(ch)) // initial cond.
s.push(ch);
else {
TreeNode tParent = new TreeNode(ch);
TreeNode t = new TreeNode(s.pop());
TreeNode t2 = new TreeNode(s.pop());
tParent.right = t;
tParent.left = t2;
s.push(ch);
System.out.println("par" + tParent.ch);
System.out.println("cright" + tParent.right.ch);
System.out.println("cleft" + tParent.left.ch);
}
}

我的测试类:

Stack stree = new Stack();

BST b = new BST();
String str = "5-3*(7-2)";
String postfix = b.convertToPosFix(str);
System.out.println(postfix);

for (char ch : postfix.toCharArray()) {
b.myInsert(ch, stree);

}

我的输出是:

par-
cright2
cleft7
par*
cright-
cleft3
par-
cright*
cleft5

最佳答案

使用TreeNodeStack,而不是字符的Stack。毕竟,您必须组合 TreeNode 而不是 char:

public void myInsert(char ch, Stack<TreeNode> s) {
if (Character.isDigit(ch)) {
// leaf (literal)
s.push(new TreeNode(ch));
} else {
// operator node
TreeNode tParent = new TreeNode(ch);

// add operands
tParent.right = s.pop();
tParent.left = s.pop();

// push result to operand stack
s.push(tParent);
}
}

树节点

public class TreeNode {
public TreeNode right = null;
public TreeNode left = null;
public final char ch;

TreeNode(char ch) {
this.ch = ch;
}

@Override
public String toString() {
return (right == null && left == null) ? Character.toString(ch) : "(" + left.toString()+ ch + right.toString() + ")";
}

}

主要

public static TreeNode postfixToTree(String s) {
Stack<TreeNode> stree = new Stack<>();

BST b = new BST();
for (char ch : s.toCharArray()) {
b.myInsert(ch, stree);
}
return stree.pop();
}

public static void main(String[] args) {
System.out.println(postfixToTree("5372-*-"));
System.out.println(postfixToTree("512+4*+3−"));
System.out.println(postfixToTree("51*24*+"));
}

这将打印

(5-(3*(7-2)))
((5+((1+2)*4))−3)
((5*1)+(2*4))

关于java - 从后缀表达式创建二叉树,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/29187998/

24 4 0
Copyright 2021 - 2024 cfsdn All Rights Reserved 蜀ICP备2022000587号
广告合作:1813099741@qq.com 6ren.com