java - 如果用户输入了字符/字符串而不是数字，如何询问用户是否要重新启动程序？

Question

我是新来的，也是 Java 新手，大约 1-2 周前开始，我想制作一个应用毕达哥拉理论的应用程序。一切都完成了，但现在我陷入了一个困境，我希望用户在输入字符或字符串而不是数字时被询问是否要重试、重新开始。

我做错了什么？这是我的代码，我也添加了注释，这样万一您不明白我想要实现的目标，它会更容易。

提前致谢!

package pitagoracalculator;
import java.util.Scanner;

public class PitagoraCalculator {

    public static void main(String[] args) {
        Scanner input = new Scanner(System.in);
            double nr1;
            double nr2;
            double ipot;
            boolean raspuns;
            String raspuns1;

            do{
                try{
                    //user is asked for first number
                    System.out.print("Introduceti primul numar: ");
                    nr1 = input.nextDouble();

                    //user is asked for second number
                    System.out.print("Introduceti al 2-lea numar: ");
                    nr2 = input.nextDouble();

                    //result of calculation
                    ipot = (nr1*nr1)+(nr2*nr2);
                    System.out.println("Rezultatul este: "+ipot+"^2");

                //in case user inserts a string/char instead of a double => error
                } catch (Exception e){
                    System.err.println("Nu ati introdus un numar.");
                    break;
                }

                //user is asked if he wants to do another calculation
                System.out.println("Doriti sa faceti un alt calcul? (da/nu)");
                raspuns1 = input.next();

                //if his answer is yes, raspuns = true, else raspuns = false
                if(raspuns1.equalsIgnoreCase("da"))
                    raspuns = true;
                else{
                    System.out.println("La revedere!");
                    raspuns = false;
                }

            //checks if the answer was true or false
            }while(raspuns == true);
    }
}

Answer 1

替换

//in case user inserts a string/char instead of a double => error
} catch (Exception e){
   System.err.println("Nu ati introdus un numar.");
   break;
}

与

//in case user inserts a string/char instead of a double => error
} catch (Exception e){
   System.err.println("Nu ati introdus un numar.");
   //clear pending input.
   if (input.hasNext()) {
        input.next();
   }
   continue;
}

“break”退出循环，“Continue”将继续下一个循环。

您还必须使用 true 初始化 raspuns 变量

boolean raspuns = true;