javascript - 将循环计数传递给 ajax 成功匿名函数

Question

在下面的示例中，key 每次都等于 d1.periods 的长度。除了将 key 作为 post 变量传递给 data 以将 key 传递给 之外，他们还有更好的方法吗？成功 匿名函数？

$.ajax({
  url: 'api/dates.json',
  dataType: 'json',
  success: function(d1){
    $('#scan-interactive').removeClass('disabled');
    for(var key in d1.periods){

      var html = "";
      html += '<tr id="'+d1.periods[key].id+'">';
      html += '<td class="month">'+d1.periods[key].month+'</td>';
      html += '<td class="week">'+d1.periods[key].week+'</td>';
      html += '<td class="days">'+d1.periods[key].days+'</td>';
      html += '<td class="dates">'+d1.periods[key].dates+'</td>';
      html += '<td class="open"></td>';
      html += '<td class="refunded"></td>';
      html += '<td class="closed"></td>';
      html += "</tr>";
      $('#scan-interactive table tbody').append(html);

      $.ajax({
        type: 'POST',
        url: 'api/count.json',
        dataType: 'json',
        data:{'created_at_min':d1.periods[key].created_at_min,'created_at_max':d1.periods[key].created_at_max},
        success: function(d2){
          $('#'+d1.periods[key].id+" .open").html(d2.open);
          $('#'+d1.periods[key].id+" .closed").html(d2.closed);
          $('#'+d1.periods[key].id+" .returns").html(d2.returns);                  
        }
      });

    }
  }
});

Answer 1

将它包裹在一个闭包中:

(function(key){

  $.ajax({
    type: 'POST',
    url: 'api/count.json',
    dataType: 'json',
    data:{'created_at_min':d1.periods[key].created_at_min,'created_at_max':d1.periods[key].created_at_max},
    success: function(d2){
      $('#'+d1.periods[key].id+" .open").html(d2.open);
      $('#'+d1.periods[key].id+" .closed").html(d2.closed);
      $('#'+d1.periods[key].id+" .returns").html(d2.returns);                  
    }
  });

})(key);