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java - 执行HQL请求

转载 作者:行者123 更新时间:2023-11-30 08:10:37 26 4
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我尝试在 HQL 中执行以下请求:

session1.createQuery("select p from Projet p inner join p.domaine d where p.site = :site")
.setString("site", selected)
.list();

但在结果中我得到的是表域的 id,而不是我想要显示的字符串列的值。PS/I 在domaine 和pojet 之间有多对一的关系。我是否忘记添加一些东西

Projet.hbm.xml

<?xml version="1.0"?>
<!DOCTYPE hibernate-mapping PUBLIC "-//Hibernate/Hibernate Mapping DTD 3.0//EN"
"http://hibernate.sourceforge.net/hibernate-mapping-3.0.dtd">
<!-- Generated 25 avr. 2015 06:50:10 by Hibernate Tools 3.4.0.CR1 -->
<hibernate-mapping>
<class name="bean.Projet" table="PROJET">
<id name="id" type="int">
<column name="ID" />
<generator class="identity" />
</id>
<property name="libelle" type="java.lang.String">
<column name="LIBELLE" />
</property>
<property name="site" type="java.lang.String">
<column name="SITE" />
</property>
<property name="finalite" type="java.lang.String">
<column name="FINALITE" />
</property>
<property name="date_actuelle" type="java.lang.String">
<column name="DATE_ACTUELLE" />
</property>
<property name="date_debut" type="java.lang.String">
<column name="DATE_DEBUT" />
</property>
<property name="date_previsionnelle" type="java.lang.String">
<column name="DATE_PREVISIONNELLE" />
</property>
<many-to-one name="domaine" class="bean.Domaine" fetch="join">
<column name="IDDOMAINE" />
</many-to-one>
<set name="assignedActeurs" table="PROJET_ACTEUR" inverse="false"
lazy="true" fetch="select" cascade="all">
<key>
<column name="ID" />
</key>
<many-to-many class="bean.Acteur">
<column name="IDACTEUR" not-null="true" />
</many-to-many>
</set>
<set name="assignedBénéficiaires" table="PROJET_BENEFICIAIRE"
inverse="false" lazy="true" fetch="select" cascade="all">
<key>
<column name="ID" />
</key>
<many-to-many class="bean.Bénéficiaire">
<column name="IDBENEFICIAIRE" not-null="true" />
</many-to-many>
</set>

<many-to-one name="chefprojet" class="bean.Chefprojet"
fetch="join">
<column name="ID_CHEF" />
</many-to-one>

</class>
</hibernate-mapping>

域.hbm.xml

<?xml version="1.0"?>
<!DOCTYPE hibernate-mapping PUBLIC "-//Hibernate/Hibernate Mapping DTD 3.0//EN"
"http://hibernate.sourceforge.net/hibernate-mapping-3.0.dtd">
<!-- Generated 25 avr. 2015 06:50:10 by Hibernate Tools 3.4.0.CR1 -->
<hibernate-mapping>
<class name="bean.Domaine" table="DOMAINE">
<id name="idDomaine" type="int">
<column name="IDDOMAINE" />
<generator class="identity" />
</id>
<property name="type_domaine" type="java.lang.String">
<column name="TYPE_DOMAINE" />
</property>
<set name="assignedProjets" table="PROJET" inverse="false" lazy="true">
<key>
<column name="IDDOMAINE" />
</key>
<one-to-many class="bean.Projet" />
</set>
<set name="assignedChantiers" table="CHANTIER" fetch="select"
cascade="all">
<key>
<column name="IDDOMAINE" not-null="true" />
</key>
<one-to-many class="bean.Chantier" />
</set>

</class>
</hibernate-mapping>

liste.jsp

<html>

<head>


<meta http-equiv="Content-Type" content="text/html; charset=ISO-8859-1">
<title>Insert title here</title>
<link rel="stylesheet" href="acceuil.css" type="text/css" />
<link rel="stylesheet" href="ajoutprojet.css" type="text/css" />

<script type="text/javascript"
src="https://ajax.googleapis.com/ajax/libs/jquery/1.4.3/jquery.min.js" /></script>

</head>

<%
List projects = (List) request.getAttribute("listProject");
if (projects == null)
projects = new ArrayList();
%>

<body>
<div class="page">
<div class="header">
<a href="index.html" id="logo"><img src="images/Captureocp.PNG"
alt="" /></a>
<ul>
<li><a href="acceuil.jsp">Home</a></li>
<li><a href="about.html">About</a></li>
<li><a href="blog.html">Blog</a></li>
<li class="selected"><a href="services.html">Services</a></li>
</ul>
</div>
</div>
</br>
</br>

<form method="post" action="liste">
<p>
<select name="sites">
<option value="">-- Choisir --</option>
<option value="Khouribga">Khouribga</option>
<option value="Casablanca">Casablanca</option>
<option value="Casablanca">Jorf Lasfar</option>
<option value="Casablanca">Benguerir</option>
<option value="Casablanca">Boucraa</option>
<option value="Casablanca">Youssoufia</option>
<option value="Casablanca">Laayoune</option>
<option value="Casablanca">Safi</option>

</select><br />

</p>
<div class="centre">

<input type="submit" value="Chercher" name="Chercher" />
</div>


<table border="1" cellpadding="3pt" align="center">
<tr>
<td>Liste des projets :</td>
</tr>


<c:forEach var="projet" items="${listProject}">
<tr>
<td><c:out value="${projet.libelle}" /></td>
<td><c:out value="${projet.site}" /></td>
<td><c:out value="${projet.finalite}" /></td>
<td><c:out value="${projet.date_actuelle}" /></td>
<td><c:out value="${projet.date_debut}" /></td>
<td><c:out value="${projet.date_previsionnelle}" /></td>
<td><c:out value="${projet.domaine.idDomaine}" /></td>
<td><c:out value="${projet.chefprojet.id_chef}" /></td>

</tr>
</c:forEach>

</table>

</form>
</body>
</html>

Servlet:

public class listeControllerServlet extends HttpServlet {

private static final long serialVersionUID = 1L;

protected void doPost(HttpServletRequest request,HttpServletResponse response) throws ServletException, IOException {


HttpSession session = request.getSession(true);


try {
Session session1=HibernateUtil.getSessionFactory().getCurrentSession();
String selected=request.getParameter("sites");
session1.beginTransaction();
List<Projet> list =
session1.createQuery("select p.id, p.site,p.libelle,p.finalite,p.date_actuelle,p.date_debut,p.date_previsionnelle, d.type_domaine from Projet p inner join p.domaine d where p.site = :site")
.setString("site", selected)
.list();
request.setAttribute("listProject", list);
request.getRequestDispatcher("liste.jsp").forward(request, response);
session1.close();

} catch (NumberFormatException e) {

e.printStackTrace();
}
}
}

最佳答案

据我了解,您希望从 Project 表中选择所有列,而仅从 Domaine 表中选择一列,因此您需要显式传递所有这些列在这样的选择查询中:

session1.createQuery("select p.id, p.libelle, p.site, p.finalite, p.date_actuelle, d.type_domaine from Projet p inner join p.domaine d where p.site = :site")
.setString("site", selected)
.list();

编辑:

当您使用此查询时,您不会获得 Project 列表,而是获得 Object 列表,因为您正在合并 Project 中的列code> 和 Domaine 因此您应该需要像这样更改代码:

Servlet:

List<Object> list = 
session1.createQuery("select p.id, p.site,p.libelle,p.finalite,p.date_actuelle,p.date_debut,p.date_previsionnelle, d.type_domaine from Projet p inner join p.domaine d where p.site = :site")
.setString("site", selected)
.list();

JSP:

在您的jsp中,您可以使用object[index]获得结果,其中index是查询的选择部分中的属性索引,这是您所需要的:

<c:forEach var="projet" items="${listProject}">
<tr>
<td><c:out value="${projet[2]}" /></td>
<td><c:out value="${projet[1]}" /></td>
<td><c:out value="${projet[3]}" /></td>
<td><c:out value="${projet[4]}" /></td>
<td><c:out value="${projet[5]}" /></td>
<td><c:out value="${projet[6]}" /></td>
<!-- you should include idDomaine and id_chef in your query to get them here -->
<td><c:out value="${projet.domaine.idDomaine}" /></td>
<td><c:out value="${projet.chefprojet.id_chef}" /></td>

</tr>
</c:forEach>

关于java - 执行HQL请求,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/30435369/

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