java - Alfresco - 在工作流程中获取用户名

Question

当我在工作流上创建时，我正在搜索 assignees 的用户名...

我用这个:

public void notify(DelegateExecution execution) {
    // get value of property mymodel:myproperty 
    Object assignees = execution.getVariable("bpm_assignees"); 
}

当我得到 bpm_assignees 时，我得到了这个:

bpm_assignees map value: [Node Type: {alfresco.org/model/content/…}person, Node Aspects: [{alfresco.org/model/content/…}ownable, {alfresco.org/model/system/1.0}referenceable, {alfresco.org/model/system/1.0}localized], Node Type: {alfresco.org/model/content/…}person, Node Aspects: [{alfresco.org/model/content/…}ownable, {alfresco.org/model/system/1.0}referenceable, {alfresco.org/model/system/1.0}localized]]

如何获取用户名？

Answer 1

那些对象是 Person NodeRefs。如果您从该节点取回属性，您将获得用户的用户名、电子邮件地址等信息。您可以看到哪些属性可用 by looking at the core content model (向下滚动到 cm:person)

假设返回的对象是一个 ActivitiScriptNodeList , 然后他们会很容易地用访问器等包裹起来，因为他们会是 ActivitiScriptNode秒。那些扩展了普通的 Alfresco JavaScript ScriptNode objects .这意味着您需要做的是:

public void notify(DelegateExecution execution){
   ActivitiScriptNodeList assignees = execution.getVariable("bpm_assignees"); 
   for (ActivitiScriptNode personNode : assignees) {
       String username = personNode.getProperties().get("cm:userName");
       String email = personNode.getProperties().get("cm:email");
       // TODO Use this
   }
}