java - 使用 Rest CXF 管理异常

Question

我只是几次接近休息服务，我想问一个简单的问题......至少我希望它很简单!

我有这项服务:

@Override
public UserTO register(UserTO userTO) {
    UserTO user=null;
    try{
    user=presentationService.register(userTO);
    }
    catch(ConstraintViolationException ex)
    {
        throw new CustomException(ex.getMessage());
    }
    return user;

}

我有这个客户:

@RequestMapping(value = "/register", method = RequestMethod.POST)
public String processRegistration(@ModelAttribute("userForm")UserTO user, Map<String, Object> model) {  
    UserTO userTO=null;
    String error="";
    Response resp;
    userTO=registerme(client, user);
}

这是异常(exception):

public class CustomException extends WebApplicationException {
public CustomException(String message) {
    super(Response.status(Response.Status.BAD_REQUEST)
        .entity(message).type(MediaType.TEXT_PLAIN).build());
}
}

我想知道如何管理客户端的异常...

例如，当我调用此服务并获取错误时，我从后端:

   2015-06-20 18:44:28 WARN  SqlExceptionHelper:143 - SQL Error: 1062, SQLState: 23000
   2015-06-20 18:44:28 ERROR SqlExceptionHelper:144 - Duplicate entry 'aa' for key 'login_UNIQUE'
   2015-06-20 18:44:28 INFO  LoggingOutInterceptor:233 - Outbound Message
   ---------------------------
   ID: 1
   Response-Code: 400
   Content-Type: text/plain
   Headers: {Content-Type=[text/plain], Date=[Sat, 20 Jun 2015 16:44:28        GMT]}
   Payload: Nn funziona! Duplicate entry 'aa' for key 'login_UNIQUE'; SQL        [n/a]; constraint [null]; nested exception is               org.hibernate.exception.ConstraintViolationException: Duplicate entry 'aa' for key 'login_UNIQUE'

在客户端我已经:

 [INFO] Starting scanner at interval of 3 seconds.
 [ERROR] /DisConnectionView/register
 javax.ws.rs.WebApplicationException 

然后 连接被拒绝。

我知道这是一个菜鸟问题，但提供一点帮助就太好了..

也许我可以将异常包装在可以随服务返回的响应元素内，但是如果我想返回一个简单的 UserTO，是否有另一种方法来管理异常并在客户端中获取类型或消息？

谢谢!

Answer 1

我建议您使用以下示例。

服务器端javax.ws.rs.ext.ExceptionMapper

public class RuntimeExceptionRestMapper implements ExceptionMapper<RuntimeException> {

    public Response toResponse(RuntimeException exception) {
        return Response.status(Response.Status.INTERNAL_SERVER_ERROR)
                //handle your response
                .type(MediaType.APPLICATION_JSON_TYPE)
                .entity(exception.getMessage())
                .build();
    }

}

服务器配置 XML

<jaxrs:server id="" address="">
    <jaxrs:serviceBeans>
        ....
    </jaxrs:serviceBeans>
    <jaxrs:providers>
        <bean class="package.RuntimeExceptionRestMapper" />
    </jaxrs:providers>
</jaxrs:server>

客户端org.apache.cxf.jaxrs.client.ResponseExceptionMapper

public class RestResponseExceptionMapper implements ResponseExceptionMapper<Exception> {

    public Exception fromResponse(Response r) {
        //throw you exception
        return new WebApplicationException(r.getStatus());
    }

}

客户端配置XML

<jaxrs:client id="service" address="" serviceClass="">
    <jaxrs:providers>
        <bean class="package.RestResponseExceptionMapper" />
    </jaxrs:providers>
</jaxrs:client>