java.sql.SQLException : Io exception: Got minus one from a read call during JDBC connection with oracle 11g

Question

嗨，我正在尝试运行一个 servlet，它从一个简单的 html 表单获取数据并将其存储在 Oracle 数据库中，并显示一条消息“数据已保存”。我使用的是 Eclipse Luna、Tomcat 7.0 和 Oracle 11g Express Edition。当我运行该程序时，出现此错误。

java.sql.SQLException: Io exception: Got minus one from a read call during JDBC connection with oracle 11g

这是我的 web.xml 文件

<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://java.sun.com/xml/ns/javaee" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd" id="WebApp_ID" version="3.0">
  <display-name>StudentManagement</display-name>
  <welcome-file-list>
    <welcome-file>index.html</welcome-file>
  </welcome-file-list>

  <servlet>
    <servlet-name>StudentRegServlet</servlet-name>
    <servlet-class>com.serv.pkg.StudentRegServlet</servlet-class>
    <init-param>
      <description></description>
      <param-name>username</param-name>
      <param-value>scott</param-value>
    </init-param>
    <init-param>
      <param-name>password</param-name>
      <param-value>tiger</param-value>
    </init-param>
    <load-on-startup>1</load-on-startup>
  </servlet>

  <servlet-mapping>
    <servlet-name>StudentRegServlet</servlet-name>
    <url-pattern>/stdreg</url-pattern>
  </servlet-mapping>

  <servlet>
  <servlet-name>CourseRegServlet</servlet-name>
  <servlet-class>com.serv.pkg.CourseRegServlet</servlet-class>
  <init-param>
  <param-name>username</param-name>
  <param-value>test</param-value>
   </init-param>

   <init-param>
   <param-name>password</param-name>
   <param-value>test</param-value>
   </init-param>

  </servlet>

  <servlet-mapping>
  <servlet-name>CourseRegServlet</servlet-name>
  <url-pattern>/coursereg</url-pattern>
  </servlet-mapping>

  <context-param>
  <param-name>driver</param-name>
  <param-value>oracle.jdbc.OracleDriver</param-value>
  </context-param>

  <context-param>
  <param-name>url</param-name>
  <param-value>jdbc:oracle:thin:@localhost:8080:XE</param-value>
  </context-param>
</web-app>

我的Servlet

package com.serv.pkg;

import java.io.IOException;
import java.io.PrintWriter;
import java.sql.Connection;
import java.sql.DriverManager;
import java.sql.PreparedStatement;
import java.sql.SQLException;

import javax.servlet.GenericServlet;
import javax.servlet.ServletConfig;
import javax.servlet.ServletContext;
import javax.servlet.ServletException;
import javax.servlet.ServletRequest;
import javax.servlet.ServletResponse;
import javax.servlet.annotation.WebServlet;

/**
 * Servlet implementation class CourseRegServlet
 */
@WebServlet("/CourseRegServlet")
public class CourseRegServlet extends GenericServlet {
    private Connection conn; 
    @Override
    public void init(ServletConfig config)throws ServletException
    {
        System.out.println("Executing init method from coursereg.html");
    ServletContext sc = config.getServletContext( );
    String driver=sc.getInitParameter("driver");
    String url=sc.getInitParameter("url");
    String username=config.getInitParameter("username");
    String password=config.getInitParameter("password");

    try {
        Class.forName(driver);
        System.out.println("driver loaded");
        conn=DriverManager.getConnection(url, username, password );
    } catch ( Exception e) {
        System.out.println("catching from init" +e);
    }

    }


    public void service(ServletRequest request, ServletResponse response) throws ServletException, IOException {
        PrintWriter out = response.getWriter();

        System.out.println("Executing service method from coursereg.html");
          int cid = Integer.parseInt(request.getParameter("cid"));
          String c_name = request.getParameter("c_name");
          int fee = Integer.parseInt(request.getParameter("fee"));

          try {
              System.out.println("exe1");
            PreparedStatement stmt=conn.prepareStatement("insert into course values(?,?,?)");
            System.out.println("exe2");
            stmt.setInt(1, cid);
            stmt.setString(2, c_name);
            stmt.setInt(3, fee);
            int i = stmt.executeUpdate();
            if(i!=0){
                System.out.println("course registered");
            }else
            {
                System.out.println("registration failed");
            }
        } catch ( Exception e) {
            System.out.println(e);
        }
          out.println("Data saved");
    }

    public void destroy(){
        try {
            System.out.println("Executing destroy method from coursereg.html");
            conn.close();
        } catch ( Exception e) {
            System.out.println(e);
        }
    }

}

Answer 1

数据库监听器的默认端口是 1521，而不是 8080(这是来自 XML DB 的默认 HTTP 端口)；所以你的网址应该是:

  <param-value>jdbc:oracle:thin:@localhost:1521:XE</param-value>

如果您的监听器位于非标准端口，则使用该端口。另外 :XE 部分意味着它将尝试与 SID XE 连接。您可能更喜欢使用服务名称，希望也是 XE，它用斜杠而不是冒号表示:

  <param-value>jdbc:oracle:thin:@localhost:1521/XE</param-value>