java - @MessageMapping 不适用于 Spring Security 和 MVC

Question

我有一个使用 Spring MVC 和安全性的应用程序。我尝试向其中添加 Websockets。我已经成功连接，但是，当我尝试向后端发送消息时 - 没有任何反应。在 Debug模式下，用@MessageMapping 注释的方法根本无法到达!我不知道为什么。我已经尝试了很多 Google 解决方案，所以现在所有配置都是下一步:

@Configuration
@EnableWebSocketMessageBroker
public class WebSocketConfig extends AbstractWebSocketMessageBrokerConfigurer {

    public WebSocketConfig() {
    }

    @Override
    public void configureMessageBroker(MessageBrokerRegistry config) {
        config.enableSimpleBroker("/topic");
        config.setApplicationDestinationPrefixes("/app");
    }

    @Override
    public void registerStompEndpoints(StompEndpointRegistry registry) {
        registry.addEndpoint("/hello1").withSockJS();
    }
}

我还为 websockets 添加了安全配置

@Configuration
public class SecuritySocketConfig extends AbstractSecurityWebSocketMessageBrokerConfigurer {

    protected boolean sameOriginDisabled() {
        return true;
    }

    protected void configureInbound(MessageSecurityMetadataSourceRegistry messages) {
        messages.simpDestMatchers("/hello1").authenticated().simpDestMatchers("/app/hello1").authenticated();//permitAll();

    }
} 

Controller 类

@Controller
public class WebsocketController {

    @MessageMapping("/hello1")
    public void send(Message message) {
        String name = message.getName();

    }
}

socket.js，导入JSP文件

;(function () {

    //init
    $(function () {
        $("#control_mode").change(app.page.controlCheck);
        connect();
    });
    var stompClient = null;


    function connect() {
        var socket = new SockJS("http://localhost:8080/hello1");
        stompClient = Stomp.over(socket);
        console.log('attempt to connect: ' +stompClient!=null);
        console.log('session id: '+ "${pageContext.session.id}");

        stompClient.connect('', '', function(frame) {
            console.log('Connected: ' + frame);
            stompClient.subscribe('/topic/greetings/', function(result) {
                getResult(result);
            });

        });
    }

    function getResult(result) {
       var isControlable= JSON.parse(greeting.body).isControlable;
        if (isControlable) {
            alert('Control was already gained')
        } else {
            $("#control_mode").prop("checked", true);
        }
    }

    app.page.controlCheck = function () {
        stompClient.send('/app/hello1', {}, JSON.stringify({'name' : "alastor" }));
        if (this.checked) {
            $("#control_mode").prop("checked", !this.checked);
        } else {
            alert('was click for release control');
        }
    };

    function disconnect() {
        stompClient.disconnect();
        console.log("Disconnected");
    }
})();

spring-security.xml(进一步导入主spring.xml)

<?xml version="1.0" encoding="UTF-8"?>
<beans:beans xmlns:beans="http://www.springframework.org/schema/beans"
             xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
             xmlns="http://www.springframework.org/schema/security"
             xsi:schemaLocation="http://www.springframework.org/schema/beans
    http://www.springframework.org/schema/beans/spring-beans.xsd
    http://www.springframework.org/schema/security
    http://www.springframework.org/schema/security/spring-security.xsd">

    <http pattern="/resources/**" security="none"/>
    <http pattern="/webjars/**" security="none"/>
    <http pattern="/rest/**" security="none"/>
    <http pattern="/favicon.ico" security="none"/>

    <http security="none" pattern="/pathWhereCSRFWillBeIgnored/**"/>
    <http>
        <intercept-url pattern="/welcome/**" access="permitAll"/>
        <intercept-url pattern="/ajax/welcome/**" access="permitAll"/>
        <intercept-url pattern="/ajax/**" access="permitAll"/>  <!--todo for testing-->

        <intercept-url pattern="/**" access="@validateService.isValid(request)"/>
        <form-login login-page="/welcome"
                    authentication-failure-url="/welcome?error=true"
                    login-processing-url="/spring_security_check"
                    authentication-success-handler-ref="directLinkHandler"/>
        <logout logout-success-url="/welcome"/>
        <csrf disabled="true"/>
    </http>

    <beans:bean class="com.promptlink.stbtp.webapi.listener.AuthenticationEventListener"/>

    <beans:bean class="com.promptlink.stbtp.service.security.util.PasswordEncoder" id="passwordEncoder"/>

    <authentication-manager alias="authenticationManager">
        <authentication-provider user-service-ref="userService">
            <password-encoder ref="passwordEncoder"/>
        </authentication-provider>
    </authentication-manager>
</beans:beans>

浏览器日志:

Opening Web Socket... stomp.js:134:99
Web Socket Opened... stomp.js:134:99
>>> CONNECT
login:
passcode:
accept-version:1.1,1.0
heart-beat:10000,10000

 stomp.js:134:99
<<< CONNECTED
version:1.1
heart-beat:0,0
user-name:qwe

 stomp.js:134:99
connected to server undefined stomp.js:134:99
Connected: CONNECTED
user-name:qwe
heart-beat:0,0
version:1.1

 socket.js:18:13
>>> SUBSCRIBE
id:sub-0
destination:/topic/greetings/

 stomp.js:134:99
>>> SEND
destination:/app/hello1
content-length:18

{"name":"alastor"}

有人知道我做错了什么吗？

第 1 版顺便说一下，当我在简单的项目中使用这个配置时，没有 Spring-Security 一切正常!

Answer 1

所以，我找到了解决方案!错误很简单。我的 WebSocketConfig 是由 IoC 上下文初始化的，而不是 MVC。我将它移动到由 MVC 上下文扫描的包中，一切都开始完美运行!如果有人有同样的情况，请确定您的 Web 套接字配置类正在由 MVC 上下文初始化。