java - 正则表达式 : How to add list as condition to satisfy regex in java

Question

我想检查下一个句子是否以wordList中已列出的单词开头？

WordList = {Hello, Namshte, Hi, Hey ...... around 500 records- dummy list here }

例如。这是第一句话。这是第二名。 你好，这是我的第三句话。

Requirement ->  "." + " " (space) + "<word from List>" 

对于简单的正则表达式，我可以写“\.\s[A-Z]”以字母开头。但我想检测以列表中的单词开头的句子。

REGEX -> \.\s[???]   -> ? how to add List here

如何正确选择第三句？

Answer 1

使用此正则表达式，以 Java 字符串形式给出:

"\\.\\s(?i:Hello|Namshte|Hi|Hey)\\b"

说明:

• \\. 比赛周期
• \\s 匹配空格
• (?i: ) 非捕获组匹配，不区分大小写。
• Hello|Namshte|Hi|Hey 匹配其中一个单词。
• \\b 匹配单词边界以防止单词匹配，例如 Hijack。

要选择整个第三句，即直到并包括下一个句点，请使用以下命令:

"\\.\\s((?i:Hello|Namshte|Hi|Hey)\\b[^.]+\\.)"

捕获组是句子。

更新代码示例:

String[] wordList = { "Hello", "Namshte", "Hi", "Hey", ...... 500 words };

StringBuilder buf = new StringBuilder();
for (String word : wordList) {
    if (buf.length() != 0)
        buf.append('|');
    buf.append(Pattern.quote(word));
}
Pattern regex = Pattern.compile("\\.\\s((?i:" + buf + ")\\b[^.]+\\.)");

String text = "This is 1st Sentence. This is 2nd place. Hello,This is my 3rd Sentence." +
              " This is 4th place. Namshte, at 5.";
Matcher m = regex.matcher(text);
while (m.find())
    System.out.println("Found: " + m.group(1));

输出

Found: Hello,This is my 3rd Sentence.
Found: Namshte, at 5.