java - Bukkit PlayerInteractEvent 不起作用

Question

我认为这是正确的，但如果我用斧头点击什么也没有发生，没有错误

我不知道出了什么问题，因为在互联网上它可以工作

package mrleaw.tools.main;

import org.bukkit.Bukkit;
import org.bukkit.Material;
import org.bukkit.entity.Player;
import org.bukkit.event.EventHandler;
import org.bukkit.event.Listener;
import org.bukkit.event.block.Action;
import org.bukkit.event.player.PlayerInteractEvent;
import org.bukkit.plugin.java.JavaPlugin;

public class Main extends JavaPlugin implements Listener{

String prefix = "§0[§4RollmopsMC | Tools§0] §5";

public void onEnable() {
    Bukkit.getConsoleSender().sendMessage(prefix + "§aDas Plugin wurde aktiviert!");
    Bukkit.getConsoleSender().sendMessage(prefix + "§6Coded by MrLeaw");
}
public void onDisable() {
    Bukkit.getConsoleSender().sendMessage(prefix + "§cDas Plugin wurde deaktiviert!");
    Bukkit.getConsoleSender().sendMessage(prefix + "§6Coded by MrLeaw");
}

@EventHandler
void onRightClickTool(PlayerInteractEvent e){
    try {
        if(e.getAction() == Action.LEFT_CLICK_AIR 
                || e.getAction() == Action.RIGHT_CLICK_AIR
                || e.getAction() == Action.LEFT_CLICK_BLOCK
                || e.getAction() == Action.RIGHT_CLICK_BLOCK){
            Player player = e.getPlayer();
            if(player.getItemInHand() != null && player.getItemInHand().getType() == Material.WOOD_AXE){
                player.sendMessage(prefix + "test");
            }
        }
    }catch(Exception exception){
    }catch(Error error){
    }
}
}

Answer 1

添加 getServer().getPluginManager().registerEvents(this, this); 到 onEnable()

根据 Bukkit API reference，您必须这样做才能注册您的监听器