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java - 使用 ResultSet 返回最后生成的键

转载 作者:行者123 更新时间:2023-11-30 07:49:56 26 4
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我正在尝试执行插入语句并在执行后获取生成的 ID。到目前为止,我已经进行了查询和准备好的语句。这是代码的一部分:PreparedStatement preparedStatement = connetion.prepareStatement(query.toString(), new String[] {"id"});添加所有参数后,我执行此操作:

preparedStatement.executeUpdate();
ResultSet resultSet = preparedStatement.getGeneratedKeys();
resultSet.next();
resultSet.getLong(1);

它抛出的异常是这样的:

java.sql.SQLException: Invalid argument(s) in call
at oracle.jdbc.driver.AutoKeyInfo.getNewSql(AutoKeyInfo.java:187)
at oracle.jdbc.driver.PhysicalConnection.prepareStatement(PhysicalConnection.java:4342)
at com.sirmabc.rfcollection.manager.FeeManagerJDBC.save(FeeManagerJDBC.java:50)
at com.sirmabc.rfcollection.test.FeeManagerJDBCTest.testSave(FeeManagerJDBCTest.java:33)
at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:62)
at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:43)
at java.lang.reflect.Method.invoke(Method.java:498)
at org.junit.runners.model.FrameworkMethod$1.runReflectiveCall(FrameworkMethod.java:50)
at org.junit.internal.runners.model.ReflectiveCallable.run(ReflectiveCallable.java:12)
at org.junit.runners.model.FrameworkMethod.invokeExplosively(FrameworkMethod.java:47)
at org.junit.internal.runners.statements.InvokeMethod.evaluate(InvokeMethod.java:17)
at org.junit.runners.ParentRunner.runLeaf(ParentRunner.java:325)
at org.junit.runners.BlockJUnit4ClassRunner.runChild(BlockJUnit4ClassRunner.java:78)
at org.junit.runners.BlockJUnit4ClassRunner.runChild(BlockJUnit4ClassRunner.java:57)
at org.junit.runners.ParentRunner$3.run(ParentRunner.java:290)
at org.junit.runners.ParentRunner$1.schedule(ParentRunner.java:71)
at org.junit.runners.ParentRunner.runChildren(ParentRunner.java:288)
at org.junit.runners.ParentRunner.access$000(ParentRunner.java:58)
at org.junit.runners.ParentRunner$2.evaluate(ParentRunner.java:268)
at org.junit.runners.ParentRunner.run(ParentRunner.java:363)
at org.eclipse.jdt.internal.junit4.runner.JUnit4TestReference.run(JUnit4TestReference.java:86)
at org.eclipse.jdt.internal.junit.runner.TestExecution.run(TestExecution.java:38)
at org.eclipse.jdt.internal.junit.runner.RemoteTestRunner.runTests(RemoteTestRunner.java:459)
at org.eclipse.jdt.internal.junit.runner.RemoteTestRunner.runTests(RemoteTestRunner.java:678)
at org.eclipse.jdt.internal.junit.runner.RemoteTestRunner.run(RemoteTestRunner.java:382)
at org.eclipse.jdt.internal.junit.runner.RemoteTestRunner.main(RemoteTestRunner.java:192)

一个非常重要的事实是,该代码在 ojdbc7 上运行良好,但是一旦我将其切换为在 ojdbc8 上运行,就会出现此错误。任何帮助将不胜感激。

最佳答案

显然 prepareStatement(query.toString(), new String[] {"id"}); 方法不再适用于 oracle 数据库。经过长时间的摸索,我发现方法 prepareStatement(query.toString(), new int[] {1}); 工作正常。问题是你在 oracle 中使用它时需要小心,它以 1 而不是 0 开头,如果你输入 0 它将再次抛出错误参数的异常。

关于java - 使用 ResultSet 返回最后生成的键,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/48096970/

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